Question

[Nguyễn mai thùy như]

GIA TRI BIEU THUC

\(\left(\dfrac{1}{2}\right)^2.\left(\dfrac{2}{3}\right)^2.\left(\dfrac{3}{4}\right)^2.............\left(\dfrac{9}{10}\right)^2\)

Answer 1

[Fa Châu De]

\(\left(\dfrac{1}{2}\right)^2.\left(\dfrac{2}{3}\right)^2.\left(\dfrac{3}{4}\right)^2.....\left(\dfrac{9}{10}\right)^2\)

\(=\left(\dfrac{1}{1}\right)^2.\left(\dfrac{1}{1}\right)^2.\left(\dfrac{1}{1}\right)^2....\left(\dfrac{1}{10}\right)^2\)

\(=\dfrac{1^2}{10^2}=\dfrac{1}{100}\)

Answer 2

[Sáng]

đơn giản vậy cơ à?? :D