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\(P=\dfrac{8a+15}{4a+1}=\dfrac{4a+4a+1+1+13}{4a+1}=\dfrac{4a+1}{4a+1}+\dfrac{4a+1}{4a+1}+\dfrac{13}{4a+1}=1+1+\dfrac{13}{4a+1}\)
Để P nguyên thì \(\dfrac{13}{4a+1}\in Z\) hay \(4a+1\in U\left\{13\right\}=\left\{\pm1;\pm13\right\}\)
- 4a+1=1 --> a=0
- 4a+1 = -1 --> a= -1/2 ( loại )
- 4a+1 = 13 --> a=3
-4a+1 = -13 --> a= -7/2 ( loại )
Vậy \(a\in Z=\left\{0;3;\right\}\) thì P nhận giá trị nguyên
h: \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
m: \(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\)
\(=\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}\)
\(=\dfrac{1}{2}-\dfrac{1}{8}=\dfrac{3}{8}\)
\(\frac{n+4}{n+1}=\frac{n+1+3}{n+1}=1+\frac{3}{n+1}\)
\(n+4⋮n+1\) khi \(3⋮n+1\Rightarrow n+1=\left\{-3;-1;1;3\right\}\Rightarrow n=\left\{-4;-2;0;2\right\}\)
6:
a: OA,Ox
OB,Oy
OB và Ax ko phải hai tia đối nhau
b: OC=4,5-1,5=3cm
OC=OB
=>O là trung điểm của BC
=1+2+(-3+4)+(-5+6)+(-7+8)+....+(-2017+2018)
=3+\(\frac{1.1008}{2}\)=507
Chúc hok tốt!!
4.17+4.84−44.17+4.84-4
=4.17+4.84−4.1=4.17+4.84-4.1
=4.17+4.84−1.4=4.17+4.84-1.4
=4.(17+84−1)=4.(17+84-1)
=4.100=4.100
=400=400
_________________
17.18−18+84.1817.18-18+84.18
=17.18−18.1+84.18=17.18-18.1+84.18
=17.18+18.(−1)+84.18=17.18+18.(-1)+84.18
=18.(17−1+84)=18.(17-1+84)
=18.100=18.100
=1800=1800
_____________________
75.12+75.9
75.12+75.9−21.2575.12+75.9-21.25
=75.(12+9)−21.25=75.(12+9)-21.25
=75.21−21.25=75.21-21.25
=75.21+21.(−25)=75.21+21.(-25)
=21.(75−25)=21.(75-25)
=21.50=21.50
=1050
\(a.\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}\\ =\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\\ b.\dfrac{7}{12}-\dfrac{27}{7}\cdot\dfrac{1}{18}\\ =\dfrac{7}{12}-\dfrac{3}{14}=\dfrac{31}{84}\\ c.\left(\dfrac{23}{11}-\dfrac{15}{82}\right)\cdot\dfrac{41}{25}\\ =\dfrac{1721}{902}\cdot\dfrac{41}{25}=\dfrac{1721}{550}\\ d.\left(\dfrac{4}{5}+\dfrac{1}{2}\right)\cdot\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\\ =\dfrac{13}{10}\cdot\left(\dfrac{-5}{13}\right)=\dfrac{-1}{2}\)