K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3

B/ \(Na\underrightarrow{\left(1\right)}Na_2O\underrightarrow{\left(2\right)}NaOH\underrightarrow{\left(3\right)}Na_2SO_4\underrightarrow{\left(4\right)}NaCl\underrightarrow{\left(5\right)}NaNO_3\underrightarrow{\left(6\right)}NaCl\underrightarrow{\left(7\right)}NaOH\)

C/\(Mg\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgCl_2\underrightarrow{\left(3\right)}Mg\left(NO_3\right)_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgSO_4\underrightarrow{\left(6\right)}MgCO_3\)

D/\(CuSO_4\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuO\underrightarrow{\left(3\right)}CuCl_2\underrightarrow{\left(4\right)}Cu\left(OH\right)_2\underrightarrow{\left(5\right)}CuSO_4\)

E/\(CuCl_2\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuSO_4\underrightarrow{\left(3\right)}Cu\underrightarrow{\left(4\right)}CuO\)

F/ \(Cu\left(OH\right)_2\underrightarrow{\left(1\right)}CuO\underrightarrow{\left(2\right)}CuCl_2\underrightarrow{\left(3\right)}Cu\left(NO_3\right)_2\underrightarrow{\left(4\right)}NaNO_3\)

G/\(Fe_2O_3\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)

H/ \(ZnCl_2\underrightarrow{\left(1\right)}Zn\left(OH\right)_2\underrightarrow{\left(2\right)}ZnCl_2\underrightarrow{\left(3\right)}NaCl\underrightarrow{\left(4\right)}NaNO_3\)

M/\(CuO\underrightarrow{\left(1\right)}CuCl_2\underrightarrow{\left(2\right)}Cu\left(OH\right)_2\underrightarrow{\left(3\right)}CuO\underrightarrow{\left(4\right)}CuSO_4\)

N/\(Fe\left(OH\right)_2\underrightarrow{\left(1\right)}FeO\underrightarrow{\left(2\right)}FeCl_2\underrightarrow{\left(3\right)}Fe\left(ỌH_2\right)\underrightarrow{\left(4\right)}FeSO_4\underrightarrow{\left(5\right)}FeCl_2\underrightarrow{\left(6\right)}Fe\left(NO_3\right)_2\)

Z/ \(Mg\left(OH\right)_2\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgSO_4\underrightarrow{\left(3\right)}MgCl_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgCl_2\underrightarrow{\left(6\right)}Mg\left(NO_3\right)_2\)

X/\(Al\left(OH\right)_3\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}AlCl_3\underrightarrow{\left(3\right)}Al\underrightarrow{\left(4\right)}Al_2\left(SO_4\right)_3\)

11
7 tháng 11 2018

g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O

2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3

3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O

4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O

7 tháng 11 2018

h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O

3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2

4. NaCl + AgNO3 → NaNO3 + AgCl↓

21 tháng 12 2017

(1) Cu(OH)2 -t0-> CuO + H2O

(2) CuO + H2 -t0-> Cu + H2O

(3) Cu + Cl2 -t0-> CuCl2

(4) CuCl2 + 2NaOH - > Cu(OH)2 + 2NaCl

(5) Cu(OH)2 + H2SO4 - > CuSO4 + 2H2O

11 tháng 10 2019

Cái nhóm (OH)2 thì xem như là 2 nguyên tử O và 2 nguyên tử H để cân bằng đúng ko ạ?

5 tháng 10 2018

a) 1: Na + O2 \(\rightarrow\) Na2O

2: Na2O + H2O \(\rightarrow\) 2NaOH

3: NaOH + SO3 \(\rightarrow\) Na2SO4 + H2O

4: Na2SO4 + BaCl2 \(\rightarrow\) NaCl + BaSO4

5 tháng 10 2018

b) 1: CaO + H2O \(\rightarrow\) Ca(OH)2

2: Ca(OH)2 + H2CO3 \(\rightarrow\) CaCO3 + 2H2O

3: CaCO3 \(\underrightarrow{t^o}\) CaO + CO2

4: CaO + HCl \(\rightarrow\) CaCl2 + H2O

11 tháng 12 2023

\(\left(1\right)2Fe+3Cl_2\xrightarrow[t^0]{}2FeCl_3\\ \left(2\right)FeCl_2+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ \left(3\right)2Fe\left(OH\right)_3\xrightarrow[t^0]{}Fe_2O_3+3H_2O\\ \left(4\right)Fe_2O_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O\)

____________

\(\left(1\right)2Al+3Cl_2\rightarrow2AlCl_3\\ \left(2\right)AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ \left(3\right)Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ \left(4\right)2Al\left(OH\right)_3\xrightarrow[t^0]{}Al_2O_3+3H_2O\\ \left(5\right)Al_2O_3+3CO\xrightarrow[]{t^0}2Al+3CO_2\\ \left(6\right)4Al+3O_2\xrightarrow[]{t^0}2Al_2O_3\\ \left(7\right)2Al+3H_2SO_4\xrightarrow[]{}Al_2\left(SO_4\right)_3+3H_2\\ \left(8\right)Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)

17 tháng 12 2017

(1) 2Na+2H2O--->2NaOH+H2

(2) 3NaOH+Al(NO3)3--->Al(OH)3+3NaNO3

(3) 2Al(OH)3--->Al2O3+3H2O

(4) 2Al2O3-đpnc---> 4Al+3O2

(5) 2Al+3H2SO4--->Al2(SO4)3+3H2

(6) Al2(SO4)3+3BaCl2--->3BaSO4+2AlCl3

17 tháng 12 2017

(1) 2Na+2H2O->2NaOH+H2

(2) 3NaOH+AlCl3->Al(OH)3+3NaCl

(3) 2Al(OH)3->Al2O3+3H2O

(4) 2Al2O3-điện phân nóng chảy->4Al+3O2

(5) 2Al+3H2SO4->Al2(SO4)3+3H2

(6) Al2(SO4)3+3BaCl2->3BaSO4+2AlCl3

9 tháng 12 2019

1) Al\(_2\)(SO\(_4\))\(_3\)+3BaCl\(_2\)→2AlCl\(_3\)+3BaSO\(_4\)

2)AlCl\(_3\)+3AgNO\(_3\)→Al(NO\(_3\))\(_3\)+3AgCl↓

3)Al(NO\(_3\))\(_3\)+3NaOH→Al(OH)\(_3\)+3NaNO\(_3\)

4)2Al(OH)\(_3\)\(\underrightarrow{to}\)Al2O3+3H2O

5)2Al2O3\(\xrightarrow[criolit]{đpnc}\)4Al+3O2

2 tháng 1 2023

\(1\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ 2\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow3BaSO_4+2AlCl_3\)

2 tháng 1 2023

PTHH hàng thứ 3 là PUHH (3)

21 tháng 12 2017

(1) \(2NaOH+SO2->Na2SO3+H2O\)

(2) \(Na2SO3+H2SO4->Na2SO4+SO2\uparrow+H2O\)

(3) \(SO3+H2O->H2SO4\)

(4) 2SO2 + \(O2\xrightarrow[V2O5]{t0}2SO3\)

(5) \(2H2SO4\left(đ,n\right)+Cu->CuSO4+SO2+2H2O\)

(6) \(Fe+CuSO4->FeSO4+Cu\)

15 tháng 4 2021

C2H5OH+3O2-to>2CO2+3H2O

b>

CO+O2-to>CO2

CO2+NaOH->NaHCO3

2NaHCO3-to>Na2CO3+H2O

Na2CO3+HCl->NaCl+H2O+CO2

NaCl+H2O-đp>NaOH+Cl2+H2

 

 

15 tháng 4 2021

\(a) C_2H_5OH + 3O_2 \xrightarrow{t^o} 2CO_2 + 3H_2O\\ b)\\ (1)2CO + O_2 \xrightarrow{t^o} 2CO_2\\ (2)CO_2 + NaOH \to NaHCO_3\\ (3)2NaHCO_3 \xrightarrow{t^o} Na_2CO_3 + CO_2 + H_2O\\ (4) Na_2CO_3 + 2HCl \to 2NaCl +C O_2 + H_2O\\ (5) 2NaCl + 2H_2O \xrightarrow{điện\ phân\ dung\ dịch} 2NaOH + H_2+ Cl_2 \)

15 tháng 4 2021

\((1) CaC_2 + 2H_2O \to Ca(OH)_2 + C_2H_2\\ (2) C_2H_2 + H_2 \xrightarrow{t^o,PbCO_3} C_2H_4\\ (3) C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH\\ (4) C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ (5) CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O\)