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Câu 3:
a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)
\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)
b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)
\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)
Câu 4:
a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)
b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)
\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)
\(=-27\cdot100-23\cdot100\)
\(=100\left(-27-23\right)\)
\(=-50\cdot100=-5000\)
c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)
d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)
\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)
\(=-1+1+\dfrac{5}{6}\)
\(=\dfrac{5}{6}\)
a) -x+18-4x-64-16=-x-4x+18-64-16=-5x-62
b) x+36+4+2x+24=x+2x+36+4+24=3x+64
c) x-23+13+2x-17+57=x+2x-23+13-17+57=3x+29
Tick nha
a: (-17)+5+8+17
\(=\left(-17+17\right)+\left(5+8\right)\)
=0+13
=13
b: \(\left(-24\right)+6+10+24\)
\(=\left(-24+24\right)+\left(6+10\right)\)
=0+16
=16
c: \(\left(-24\right)+6+\left(-10\right)+24\)
\(=\left(-24+24\right)+\left(6-10\right)\)
=0+(-4)
=-4
d: \(\left(-456\right)+2021-544\)
\(=2021-\left(456+544\right)\)
=2021-1000
=1021
e: \(\left(-1075\right)-29-\left(-1075\right)\)
\(=-1075+1075-29\)
=0-29
=-29
f: \(\left(-135\right)+48+140-\left(-5\right)\)
\(=48+\left(-135+140+5\right)\)
=48+10
=58
g: \(329+64+\left(-394\right)+36\)
\(=\left(329-394\right)+\left(64+36\right)\)
=100-65
=35
h: \(\left(-427\right)+\left(-123\right)+23+27\)
\(=\left(-427+27\right)+\left(-123+23\right)\)
=-400-100
=-500
a)-(23+17-64)-(-24)
=-23-17+64+24
=(-23-17)+(64+24)
=-40+88
=48
b)(12+64-13)-(23-26-27)
=12+64-13-23+26+27
=(12-23)+(64+26)-(13-27)
=-11+90+14
=79+14
=93
a)=-23-17+64+24
=48
b)=12+64-13-23+26+27
=35