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\(B=\left(3+3^3+3^5\right)+3^6\left(3+3^3+3^5\right)+.............+3^{24}\left(3+2^3+3^5\right)\)
\(B=273+273\cdot3^6+.............+273\cdot3^{24}\)
\(B=273\left(1+3^6+.......+3^{24}\right)⋮273\)
d: Ta có: \(D=5^3+6^3+59\)
\(=125+216+59\)
\(=400=20^2\)
`A = 2 + 2^2+ ... + 2^2017`
`=> 2A = 2^2 + 2^3 + ... + 2^2018`
`=> 2A - A = (2^2 + 2^3 + ... + 2^2018) - (2 + 2^2 + ... +2^2017)`
`=> A = 2^2018 - 2`
`B = 1 + 3^2 + ... + 3^2018`
`=> 3^2B = 3^2 + 3^4 + ... + 3^2020`
`=> 9B-B =(3^2 + 3^4 + ... + 3^2020) - (1 + 3^2 + ... + 3^2018`
`=> 8B = 3^2020 - 1`
`=> B = (3^2020 - 1)/8`
`C = 5 + 5^2 - 5^3 + ... + 5^2018`
`=> 5C = 5^2 + 5^3 - 5^4 + ... +5^2019`
`=> 5C + C = ( 5^2 + 5^3 - 5^4 + ... 5^2019) + (5 + 5^2 - 5^3 + ... + 5^2018)`
`=> 6C = 55 + 5^2019`
`=> C = (5^2019 + 55)/6`
a) 23 = 8; 24 = 16; 25 = 32; 26 = 64; 27 = 128; 28 = 256; 29 = 512; 210 = 1024
b) 32 = 9; 33 = 27; 34 = 81; 35 = 243
c) 42 = 16; 43 = 64; 44 = 256
d) 52 = 25; 53 = 125; 54 = 625
c) 62 = 36; 63 = 216; 64 = 1296
a) 23 = 8; 24 = 16; 25 = 32; 26 = 64; 27 = 128; 28 = 256; 29 = 512; 210 = 1024
b) 32 = 9; 33 = 27; 34 = 81; 35 = 243
c) 42 = 16; 43 = 64; 44 = 256
d) 52 = 25; 53 = 125; 54 = 625
e) 62 = 36; 63 = 216; 64 = 1296
HT
a) 38 : 34 + 22 x 23 = 113
b) 3 x 42 - 2 . 3 = 42
c) 46 . 34 . 95 : 612 = 9
d) 212 . 14 . 125 : 353 . 6 = 108
e) 453 . 204 .182 : 1805 = 25
#BạcHà#
bn ơi ghi cả cách làm nữa bn
ai lm lun cách làm mk sẽ k cho 2 k lun
22 = 4; 23 = 8; 24 = 16; 25 = 32; 26 = 64
27 = 128; 28 = 256; 29 = 512; 210 = 1024
32 = 9; 33 = 27; 34 = 81; 35 = 243
42 = 16; 43 = 64; 44 = 256
52 = 25; 53 = 125; 54 = 625
a) \(A=\left(5+5^2\right)+5^2\left(5+5^2\right)+...+5^6\left(5+5^2\right)=30+5^2.30+...+5^6.30\)
\(=30\left(1+5^2+...+5^6\right)⋮30\Rightarrowđpcm\)
b) \(B=\left(3+3^3+3^5\right)+3^6\left(3+3^3+3^5\right)+...+3^{24}\left(3+3^3+3^5\right)=273+3^6.273+...+3^{24}.273\)
\(=273.\left(1+3^6+...+3^{24}\right)⋮273\Rightarrowđpcm\)
a: \(B=5\left(1+5+5^2+5^3\right)+5^5\left(1+5+5^2+5^3\right)\)
\(=156\cdot5\cdot\left(1+5^4\right)\)
\(=780\left(1+5^4\right)⋮30\)
b: \(B=\left(3+3^3+3^5\right)+...+3^{24}\left(3+3^2+3^5\right)\)
\(=273\cdot\left(1+...+3^{24}\right)⋮273\)