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Lời giải:
a.
$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$
b.
$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$
c.
$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$
$x=(-1).\frac{-8}{9}=\frac{8}{9}$
Bài 1:
a) x + 19 - 35 = 36 b) 34 - x + 611 = 56
x + 19 = 36 + 35 34 - x = 56 - 611
x + 19 = 1110 34 - x = 1966
x = 1110 - 19 x = 1966 + 34
x = 8990 x = 137132
Bài 2
a) x : 13/16 = 5/8 b)x - 14/28 = 6/9 + 8/25
x = 5/8 * 13/16 x - 14/28 = 74/75
x = 65/128 x = 74/75 + 14/28
x = 223/150
Bài 3
a)62/7 * x = 29/9 : 3/56 b)1/5 : x = 1/5 + 1/7
62/7 * x = 1624/27 1/5 : x = 12/35
x = 1624/27 : 62/7 x = 12/35 * 1/5
x = 5684/637 x = 12/175
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)
Bài 1:
a) x + \(\frac{1}{9}\) - \(\frac{3}{5}\) = \(\frac{3}{6}\) b) \(\frac{3}{4}\) - x + \(\frac{6}{11}\) = \(\frac{5}{6}\)
x + \(\frac{1}{9}\) = \(\frac{3}{6}\) + \(\frac{3}{5}\) \(\frac{3}{4}\) - x = \(\frac{5}{6}\) - \(\frac{6}{11}\)
x + \(\frac{1}{9}\) = \(\frac{11}{10}\) \(\frac{3}{4}\) - x = \(\frac{19}{66}\)
x = \(\frac{11}{10}\) - \(\frac{1}{9}\) x = \(\frac{19}{66}\) + \(\frac{3}{4}\)
x = \(\frac{89}{90}\) x = \(\frac{137}{132}\)
Bài 2
a) x : 13/16 = 5/8 b)x - 14/28 = 6/9 + 8/25
x = 5/8 * 13/16 x - 14/28 = 74/75
x = 65/128 x = 74/75 + 14/28
x = 223/150
Bài 3
a)62/7 * x = 29/9 : 3/56 b)1/5 : x = 1/5 + 1/7
62/7 * x = 1624/27 1/5 : x = 12/35
x = 1624/27 : 62/7 x = 12/35 * 1/5
x = 5684/637 x = 12/175
\(a,97-7\left(x-11\right)=34\)
\(7\left(x-11\right)=63\)
\(x-11=9\)
\(x=20\)
Vậy \(x=20\).
\(b,4^3-\left(25+x\right)=6^2\)
\(64-\left(25+x\right)=36\)
\(25+x=28\)
\(x=3\)
Vậy \(x=3.\)
\(c,\left|x-5\right|-9=-3\)
\(\left|x-5\right|=6\)
\(\Rightarrow\orbr{\begin{cases}x-5=-6\\x-5=6\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\x=11\end{cases}}}\)
Vậy \(x\in\left\{-1;11\right\}\).
a) Ta có : 97 - 7 . ( x - 11 ) = 34
<=> 7. ( x -1 ) = 97 - 34
<=> 7. ( x - 1 ) = 63
<=> x - 1 = 63 : 7
<=> x - 1 = 9
<=>x = 9 + 1
<=> x = 10
Vậy x = 10
b)Cách 1 : Ta có : 43 - ( 25 + x ) = 62
<=> 64 - ( 25 + x ) = 36
<=> 25 + x = 64 -36
<=> x = 28 - 25
<=> x = 3
Vậy x = 3
Cách 2 :Ta có : 43 - ( 25 + x ) = 62
<=> 64 - 25 -x = 36
<=> 39 -x = 36
<=> x = 39 - 36
<=> x = 3
Vậy x = 3
c)Ta có : | x - 5 | - 9= -3
<=>| x - 5 | = ( -3 ) + 9
<=> | x - 5| = 6
\(\Leftrightarrow\orbr{\begin{cases}x-5=6\\x-5=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-1\end{cases}}}\)
Vậy x = { 11 ; -1 }