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4 tháng 8 2017

12 x 35 + 35 x 182 - 35 x 94

= 35 x ( 12 + 182 - 94 ) 

= 35 x 100

= 3500 

4 tháng 8 2017

Ta có:

a) 12 x 35 + 35 x 182 - 35 x 94

= ( 12 + 182 - 94 ) x 35

= 100 x 35

= 3 500

b) Sửa đề: 

   125 x 98 - 125 x 46 - 52 x 125

= 125 x ( 98 - 46 - 52 )

= 125 x 0

= 0

c) 17 x 39 + 116 x 83 x 17 x 23

= 663 + 3764548

= 3765211

d) Sửa đề.

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\) 

\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{10.11}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\)

\(=\frac{1}{1}-\frac{1}{11}\)

\(=\frac{10}{11}\)

Bạn chép đề sai khá nhiều nhé!

27 tháng 12 2015

125 x 98 + 125 x 46-52 x 25

125 x (98+46)  - 52 x 25

125 x 144 -52 x25

18000 -1300

=16700

=

14 tháng 2 2019

c)

\(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+....+\left(1-\frac{1}{42}\right)+\left(1-\frac{1}{56}\right)\)

\(\left(1+1+1+....+1+1\right)+\left(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{6\times7}+\frac{1}{7\times8}\right)\)(Có  7 số 1)

\(7+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)

\(7+1-\frac{1}{8}=\frac{63}{8}\)

Gợi ý 1 bài c) còn d) e) cũng làm như vậy nhé

Chúc bạn học tốt !!!

25 tháng 10 2017

a,48x19+48x115+124x52

=48x(19+115)+124x52

=48x124+124x52

=124x(48+52)

=124x100

=12400

b,27x121-87x27+73x34

=27x(121-87)+73x34

=27x34+73x34

=34x(27+73)

=34x100

=3400

c,125x98-125x46-52x25

=125x(98-46)-52x25

=125x52-52x25

=52x(125-25)

=52x100

=5200

d,136x23+136x17-40x36

=136x(23+17)-40x36

=136x40-40x36

=40x(136-36)

=40x100

=4000

e,17x93+116x83+17x23

=17x93+17x23+116x83

=17x(93+23)+116x83

=17x116+116x83

=116x(17+83)

=116x100

=11600

g,19x27+47x81+19x20

=19x27+19x20+47x81

=19x(27+20)+47x81

=19x47+47x81

=47x(19+81)

=47x100

=4700

h,87x23+13x93+70x87

=87x23+70x87+13x93

=87x(23+70)+13x93

=87x93+13x93

=93x(87+13)

=93x100

=9300

Nhớ like mik nhé!^-^ Mất bao thời gian của mik đấy!

14 tháng 7 2017

Sửa đề : \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x\left(x+1\right)}=\frac{98}{100}\)

\(\Leftrightarrow\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{98}{100}\)

\(\Leftrightarrow\frac{2-1}{1\times2}+\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+....+\frac{\left(x+1\right)-x}{x\left(x+1\right)}=\frac{98}{100}\)

\(\Leftrightarrow\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+....+\frac{1}{x}-\frac{1}{\left(x+1\right)}=\frac{98}{100}\)

\(\Leftrightarrow\frac{1}{1}-\frac{1}{\left(x+1\right)}=\frac{98}{100}\)

\(\Leftrightarrow\frac{1}{\left(x+1\right)}=\frac{1}{1}-\frac{98}{100}\)

\(\Leftrightarrow\frac{1}{\left(x+1\right)}=\frac{1}{50}\)

\(\Leftrightarrow x=50-1=49\)

14 tháng 7 2017

Sửa đề: \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x\left(x+1\right)}=\frac{98}{100}\)

(=) \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{98}{100}\)

(=)\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{98}{100}\)

(=)\(1-\frac{1}{x+1}=\frac{98}{100}\)

(=)\(\frac{1}{x+1}=1-\frac{98}{100}\)

(=)\(\frac{1}{x+1}=\frac{1}{50}\)=> \(x+1=50\)

                                    \(x=50-1\)

                                    \(x=49\)

T_i_c_k cho mình nha,thanks you so much!

30 tháng 6 2017

A= 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90 

=1/(1.2)+1/(2.3)+1/(3.4)+1/(4.5) +1/(5.6)+1/(6.7)+1/(7.8) +1/(8.9)+1/(9.10) 

=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5.+1/5-1/6... +1/9-1/10 

=1-1/10 

=9/10

30 tháng 6 2017

Me too ! 

Ta có: \(A=\dfrac{1-0.5\cdot\left(3.84-2.4\right):0.8}{\dfrac{4}{5}-\left(1\dfrac{1}{3}-2\dfrac{1}{6}\right)-1.5}\)

\(=\dfrac{1-0.5\cdot1.44:0.8}{\dfrac{4}{5}-\left(\dfrac{4}{3}-\dfrac{13}{6}\right)-\dfrac{3}{2}}\)

\(=\dfrac{1-0.9}{\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{3}{2}}=\dfrac{0.1}{\dfrac{2}{15}}=\dfrac{3}{4}\)

Giải:

A=1-0,5.(3,84-2,4):0,8 / 4/5-(1 1/3 - 2 1/6)-1,5

A=1-0,5.1,44:0.8 / 4/5-(4/3-13/6)-3/2

A=1-0.9 / 4/5-(-5/6)-3/2

A=0.1 / 2/15

A= 1/10 : 2/15

A=3/4

Chúc bạn học tốt!

19 tháng 10 2017

a)\(48x19+48x115+134x52\)

\(=48x\left(19+115\right)+134x52\)

\(=48x132+132x52\)

\(=132x\left(48+52\right)\)

\(=132x100=13200\)

b)\(27x121-87x27+73x34\)

\(=27x\left(121-87\right)+73x34\)

\(=27x34+73x34\)

\(=34x\left(27+73\right)\)

\(=34x100=3400\)

c)\(125x98-125x46-52x25\)

\(=125x\left(98-46\right)-52x25\)

\(=125x52-52x25\)

\(=52x\left(125-25\right)\)

\(=52x100=5200\)

d)\(136x23+136x17-40x36\)

\(=136x\left(23+17\right)-40x36\)

\(=136x40-40x36\)

\(=40x\left(136-36\right)\)

\(=40x100=4000\)

e)\(17x93+116x83+17x23\)

\(=17x\left(93+23\right)+116x83\)

\(=17x116+116x83\)

\(=116x\left(17+83\right)\)

\(=116x100=11600\)

g)\(19x27+47x81+19x20\)

\(=19x\left(27+20\right)+47x81\)

\(=19x47+47x81\)

\(=47x\left(19+81\right)\)

\(=47x100=4700\)

h)\(87x23+13x93+70x87\)

\(=87x\left(23+70\right)+13x93\)

\(=87x93+13x93\)

\(=93x\left(87+13\right)\)

\(=93x100=9300\)

Mk đã mất công zậy rùi nên mong mọi người k mk nhé

19 tháng 10 2017

a) = 13400

b) = 4714

c) = 5200

d) = 4000

e) = 11600

g) = 4700

h) = 9300

25 tháng 9 2015

a Ta có

(1+2+3....+100).(1^2+2^2+..+10^2).(13.5.3.37-13.15.37)

=(1+2...+100).(1^2+2^2+...+10^2).0=0

b Ta co

19.64+76.34=19.4.16+76.34=76.16+76.34=76(16+34)=76.50=3100 ( cau c tuong tu )

4 tháng 7 2019

= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9

= 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/9

=1-1/9

=8/9

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)

=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)

\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)

\(1-\frac{1}{9}\)

\(\frac{8}{9}\)