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a ) x/4 = 16/128
Áp dụng tính chất phân số bằng nhau ta có 4 . 16 = x . 128
64 = x . 128
=> x = 0,5
b ) \(1\frac{5}{6}=\frac{-x}{5}\)
11/6 = -x/5
Áp dụng tính chất phân số bằng nhau ta có 11 . 5 = 6 . -x
=> không tồn tại x ( vì 11 . 5 kết quả là dương , 6 . -x sẽ có kết quả âm , dương không thể bằng âm
c ) 4,25 : 8 = -3,5 : x
4,25 = -3.5 . 17/-14
=> 8 = x . 17/-14
=> x = -112/17
bai 2:
x.128=16.4
x.128=64
x=64:128=1/2
b,11.5=-6x
55=-6x
x=-55/6
c,17/32=-3,5:x
x= -96/85
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\(\frac{x}{4}=\frac{16}{128}\)
\(x=\frac{16\times4}{128}\)
\(x=\frac{1}{2}\)
***
\(1^5_6=-\frac{x}{5}\)
\(\frac{x}{5}=-\frac{11}{6}\)
\(x=-\frac{11\times5}{6}\)
\(x=-\frac{55}{6}\)
***
\(4,25\div8=3,5\div x\)
\(\frac{3,5}{x}=\frac{4,25}{8}\)
\(x=\frac{3,5\times8}{4,25}\)
\(x=\frac{112}{17}\)
a) \(\frac{x}{4}=\frac{16}{128}=\frac{1}{8}\)
=> 8x = 4
=> x = 4 : 8 \(=\frac{1}{2}\)
b) \(1\frac{5}{6}=\frac{-x}{5}\)
=> \(\frac{11}{6}=\frac{-x}{5}\)
=> 11.5 = -x.6
=> 55 = x.(-6)
=> \(x=\frac{55}{-6}=-\frac{55}{6}\)
c) 4,25 : 8 = 3,5 : x
=> \(\frac{17}{4}.\frac{1}{8}=\frac{7}{2}:x\)
=> \(\frac{17}{32}=\frac{7}{2}:x\)
=> \(x=\frac{7}{2}:\frac{17}{32}\)
=> \(x=\frac{7}{2}.\frac{32}{17}=\frac{112}{17}\)
a) \(\frac{x}{4}=\frac{16}{128}\)
\(x.128=4.16\)
\(x.128=64\)
\(x=64:128\)
\(x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
b) \(\frac{11}{6}=\frac{-x}{5}\)
\(11.5=\left(-x\right).6\)
\(55=\left(-x\right).6\)
\(-x=55:6\)
\(-x=\frac{55}{6}\)
\(\Rightarrow x=-\frac{55}{6}\)
Vậy \(x=-\frac{55}{6}\)
c) \(4,25:8=-3,5:x\)
\(\frac{17}{32}=-3,5:x\)
\(x=\frac{-35}{10}:\frac{17}{32}\)
\(x=-6\frac{10}{17}\)
Vậy \(x=-6\frac{10}{17}\)
\(a.\)
\(\frac{x}{4}=\frac{16}{128}\)
\(\Rightarrow x=\frac{16.4}{128}\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy : \(x=\frac{1}{2}\)
\(b.\)
\(\frac{11}{6}=\frac{-x}{5}\)
\(\Rightarrow x=\frac{11.5}{-6}\)
\(\Rightarrow x=-\frac{55}{6}\)
Vậy : \(x=-\frac{55}{6}\)
\(c.\)
\(\frac{4,25}{8}=\frac{-3,5}{x}\)
\(\Rightarrow x=\frac{-3,5.8}{4,25}\)
\(\Rightarrow x=-6\frac{10}{7}\)
Vậy : \(x=-6\frac{10}{7}\)
a) \(\dfrac{x}{4}=\dfrac{16}{128}\Rightarrow x=\dfrac{4.16}{128}=\dfrac{1}{2}=0,5\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\Rightarrow-x=\dfrac{5.11}{6}=\dfrac{55}{6}\Rightarrow x=-\dfrac{55}{6}\)
c) \(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\Rightarrow x=\dfrac{8.\left(-3,5\right)}{4,25}=-\dfrac{112}{17}\)
a,X/4=16/28
=»x/4=4/7
=4/7.4
=7
b,1/5/6=-x/5
-x/5=11/6
X=11/6.5
X=55/6
a)\(\dfrac{x}{4}=\dfrac{16}{128}\)
\(\Leftrightarrow\dfrac{x}{4}=\dfrac{1}{8}\)
\(\Rightarrow x=\dfrac{1.4}{8}=\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\)
\(\Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\)
\(\Rightarrow-x=\dfrac{11.5}{6}=\dfrac{-55}{6}\)
c)\(4,25:8=-3,5:x\)
\(\Leftrightarrow\dfrac{17}{32}=\dfrac{-3,5}{x}\)
\(\Rightarrow x=\dfrac{\left(-3,5\right).32}{17}=-\dfrac{112}{17}\)
Tìm x
a)\(\dfrac{x}{4}\)=\(\dfrac{16}{128}\)
\(\Rightarrow\)x.128=16.4
x.128=64
x=64:128
x=\(\dfrac{1}{2}\)
Vậy x=\(\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}\)=\(\dfrac{-x}{5}\)
\(\dfrac{11}{6}\)=\(\dfrac{-x}{5}\)
-x:5=\(\dfrac{11}{6}\)
-x=\(\dfrac{11}{6}\).5
-x=\(\dfrac{55}{6}\)
\(\Rightarrow\)x=\(\dfrac{-55}{6}\)
Vậy x=\(\dfrac{-55}{6}\)
c)4,25:8 = -3,5:x
-3,5:x=\(\dfrac{17}{4}\)
x=-3,5:\(\dfrac{17}{4}\)
x=\(\dfrac{14}{17}\)
Vậy x=\(\dfrac{14}{17}\)
\(a,\dfrac{x}{4}=\dfrac{16}{128}\\ \Leftrightarrow128x=4.16\\ \Leftrightarrow128x=64\\ \Leftrightarrow x=\dfrac{1}{2}\)
Vậy...
\(b,1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow-6x=25\\ \Leftrightarrow x=-\dfrac{25}{6}\)
Vậy...
\(c,4,25:8=-3,5:x\\ \Leftrightarrow4,25x=-3,5.8\\ \Leftrightarrow x=-28:4,25\\ \Leftrightarrow x=-\dfrac{112}{17}\)
Vậy...
Câu a :
\(\dfrac{x}{4}=\dfrac{16}{128}\) \(\Leftrightarrow x.128=4.16\) \(\Rightarrow x=\dfrac{1}{2}\)
Câu b :
\(1\dfrac{5}{6}=-\dfrac{x}{5}\) \(\Leftrightarrow11.5=-x.6\) \(\) \(\Rightarrow-x=-\dfrac{55}{6}\)
Câu c :
\(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\) \(\Leftrightarrow4,25.x=8.-3,5\) \(\Rightarrow x=-\dfrac{112}{17}\)
a,Ta có : x.128=16.4
x.128=64
Suy ra : x=1/2
b,\(1\dfrac{5}{6}=\dfrac{11}{6}\)
Ta có ; 11.5=-x.6
-x.6=55
Suy ra : x=-55/6
c,Ta có : 4,25.x=-3,5.8
4,25.x=-28
Suy ra : x=-112/17
\(3\frac{1}{2}-\frac{1}{2}.\left(-4,25-\frac{3}{4}\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.\left(-4,25-0,75\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.\left(-5\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.5.\frac{4}{5}\)
\(=\frac{7}{2}-2\)
\(=\frac{7}{2}-\frac{4}{2}\)
\(=\frac{3}{2}\)
\(\frac{3}{7}.1\frac{1}{2}+\frac{3}{7}.0,5-\frac{3}{7}.9\)
\(=\frac{3}{7}.\left(\frac{3}{2}+\frac{1}{2}-9\right)\)
\(=\frac{3}{7}.\left(2-9\right)\)
\(=\frac{3}{7}.\left(-7\right)\)
\(=-3\)
\(\frac{125^{2016}.8^{2017}}{50^{2017}.20^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^2\right)^{2017}.2^{2017}.\left(2^2\right)^{2018}.5^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^3\right)^{2017}.\left(2^3\right)^{2017}.2.5}=\frac{1}{5^4.2}=\frac{1}{1250}\)( tính nhẩm, ko chắc đúng )
1
a) \(3\frac{1}{2}-\frac{1}{2}\cdot\left(-4,25-\frac{3}{4}\right)^2\) : \(\frac{5}{4}\)
= \(3\cdot25:\frac{5}{4}\)
= \(3\cdot\left(25:\frac{5}{4}\right)\)
=\(3\cdot20\)
=60
b)=\(\frac{3}{7}\cdot\left(1\frac{1}{2}+0,5-9\right)\)
=\(\frac{3}{7}\cdot\left(-7\right)\)
=\(-3\)
c) =
a)\(\frac{x}{4}=\frac{16}{128}=\frac{1}{8}\)
\(\Rightarrow x=\frac{4}{8}=\frac{1}{2}\)
b)\(1\frac{5}{6}=\frac{11}{6}=\frac{-x}{5}\)
\(\Rightarrow x=\frac{11\times-5}{6}=\frac{-55}{6}\)
c)\(\frac{4,25}{8}=\frac{3,5}{x}\Rightarrow x=\frac{8\times3,5}{4,25}=\frac{112}{17}\)