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\(A=20\times21+21\times22+...+99\times100\)
\(3\times A=20\times21\times\left(22-19\right)+21\times22\times\left(23-20\right)+...+99\times100\times\left(101-98\right)\)
\(=20\times21\times22-19\times20\times21+...+99\times100\times101-98\times99\times100\)
\(=99\times100\times101-19\times20\times21\)
Suy ra \(A=\frac{99\times100\times101-19\times20\times21}{3}=360640\)
\(B=3\times4\times5+4\times5\times6+...+98\times99\times100\)
\(4\times B=3\times4\times5\times\left(6-2\right)+4\times5\times6\times\left(7-3\right)+...+98\times99\times100\times\left(101-97\right)\)
\(=3\times4\times5\times6-2\times3\times4\times5+...+98\times99\times100\times101-97\times98\times99\times100\)
\(=98\times99\times100\times101-2\times3\times4\times5\)
Suy ra \(B=\frac{98\times99\times100\times101-2\times3\times4\times5}{4}=24497520\)
a , x + 8 - x - 22
= ( x - x ) + 8 - 22
= 0 - 14 = - 14
b , - x - a + 12 + a
= ( a - a ) - x + 12
= 0 - x + 12
= - 98 + 12 = -86
c , a - m + 7 + m - 8
= - m + m + a + 7 - 8
= 0 + a - 1
= 61 - 1 = 60
d , m - 24 - x + 24 + x
= ( - 24 + 24 ) - x + x + m
= 0 + 0 - 25 = - 25
Cho x = ‐ 98; a = 61; m = ‐ 25.
a﴿ x + 8 ‐ x ‐ 22.
= ﴾‐98﴿ + 8 ‐ ﴾‐98﴿ ‐ 22
= ﴾‐90﴿ + 98 ‐ 22
= 8 ‐ 22 = ‐ 14.
b﴿ ‐x ‐ a + 12 + a
= ‐﴾‐98﴿ ‐ 61 + 61
= 98 + ﴾ 61 ‐ 61﴿
= 98 + 0 = 98.
c﴿ ‐m + 7 + m ‐ 8
= ‐﴾‐25﴿ + 7 + ﴾‐25﴿ ‐ 8
= [25 + ﴾‐25﴿] + 7 ‐ 8
= 0 + 7 ‐ 8
= ‐1.
d﴿ m ‐ 24 ‐ x + 24 + x
= ﴾‐25﴿ ‐ 24 ‐﴾‐98﴿ + 24 + ﴾‐98﴿
= ﴾‐25﴿ ‐ 24 + 98 + 24 ‐ 98
=﴾‐25﴿ + [﴾24 ‐ 24﴿ + ﴾ 98 ‐ 98﴿
= ‐25.
ta có: 315 < 3158; 3157 < 3158
=> 315 x 3157 < 3158 x 3158
=> A < B
( x - 41 ) . 109 = 74 . 215 - 74 . 106
( x - 41 ) . 109 = 74 . ( 215 - 106 )
( x - 41 ) . 109 = 74 . 109
x - 41 = 74 . 109 : 109
x - 41 = 74
x = 74 + 41
x = 115
Vậy x = 115
=))
\(\left(x-41\right)\times109=74\times215-74\times106\)
\(\left(x-41\right)\times109=74\left(215-106\right)=74.109\)
Chia cả hai vế cho 109 \(\Rightarrow x-41=74\)
\(x=74-41=34\)
\(M=3^1+3^3+....+3^{2015}\)
\(M=\left(3^1+3^3+3^5+3^7+3^9+3^{11}\right)+......+\left(3^{2005}+3^{2007}+3^{2009}+3^{2011}+3^{2013}+3^{2015}\right)\)
\(M=\left(3^1+3^3+3^5+3^7+3^9+3^{11}\right)+....+3^{2004}.\left(3^1+3^3+3^5+3^7+3^9+3^{11}\right)\)
\(M=199290+......+3^{2004}.199290\)
MÀ \(199290⋮70\)
\(\Rightarrow M=199290+.....+2^{2004}.199290⋮70\)
HAY \(M=3^1+3^3+......+3^{2015}⋮70\left(đpcm\right)\)
x=(1+2+3-4-5-6)+...+(97+98+99-100-101-102)
x=-9+...+-9
x=-9.17
x=-153
A= 2.2.2+ 2.2.2.2.2+ 2.2.2.2.2.2.2+ ..........+ 2.2.2.2.2.2.2.2..2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2.2..2.2= tu lam
Cách 1 :
A = 2.4 + 4.6 + 6.8 + ... + 98.100
6.A = 2.4.6 + 4.6.6 + 6.8.6 +...+ 98.100.6
6.A = 2.4.6 + 4.6.( 8 - 2 ) + 6.8.( 10 - 4 ) +...+ 98.100.( 102 - 96 )
6.A = 2.4.6 + 4.6.8 - 2.4.6 + 6.8.10 - 4.6.8 + ... + 98.100.102 - 96.98.100
6.A = ( 2.4.6 - 2.4.6 ) + ( 4.6.8 - 4.6.8 ) + ( 6.8.10 - 6.8.10 ) + ... + ( 96.98.100 - 96.98.100 ) + 98.100.102
6.A = 98.100.102
A = 98.100.102 : 6 = 166600
Cách 2 ( mik chịu )
Áp dụng công thức tính dãy số ta có:
\(\frac{\left[\left(x-98\right):4+1\right].\left(x+98\right)}{2}=15050\)
\(\Rightarrow\left(\frac{x-98}{4}+1\right).\left(x+98\right)=30100\)
\(\Rightarrow\left(\frac{x-98+4}{4}\right)\left(x+98\right)=30100\)
\(\Rightarrow\left(\frac{x+94}{4}\right)\left(x+98\right)=30100\)
\(\Rightarrow\frac{x+94}{4}x+\frac{x+94}{4}.98=30100\)
\(\Rightarrow\frac{x^2+94x}{4}+\frac{98x+9212}{4}=30100\)
\(\Rightarrow x^2+192x+9212=120400\)
\(\Rightarrow x^2+192x=111188\)
\(\Rightarrow x.\left(x+192\right)=111188\)
\(\Rightarrow x=252\)
số số hạng là (x-98):4+1=x/4-49/2+1=x/4-47/2=(x-94)/4
tổng là (x+98).(x-94)/4:2=(x+98).(x-94)/2=15050
=>(x+98).(x-94)=30100
đến đây tớ xin bái