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\(a,5\frac{1}{4}+3,25-50\%+y=15,25\)
\(\Leftrightarrow5,25+3,25-\frac{50}{100}+y=15,25\)
\(\Leftrightarrow5,25+3,25-0,5+y=15,25\)
\(\Leftrightarrow8+y=15,25\)
\(\Leftrightarrow y=15,25-8=7,25\)
\(b,(y-3):2=2010\)
\(\Leftrightarrow y-3=4020\)
\(\Leftrightarrow y=4023\)
\(\dfrac{11}{49}\times\dfrac{9}{1}\times\dfrac{7}{33}=\dfrac{11\times9\times7}{7\times7\times1\times11\times3}=\dfrac{9}{21}=\dfrac{3}{7}\)
\(A=\frac{10}{5.7}+\frac{10}{7.9}+\frac{10}{9.11}+...+\frac{10}{33.35}\)
\(\Rightarrow A=10.\left(\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+...+\frac{1}{33.35}\right)\)
Đặt \(B=\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+...+\frac{1}{33.35}\)
\(\Rightarrow2B=\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{33.35}\)
\(\Rightarrow2B=\frac{1}{5}-\frac{1}{35}=\frac{6}{35}\)
\(\Rightarrow B=\frac{3}{35}\)
\(\Rightarrow A=10.\frac{3}{35}=\frac{30}{35}=\frac{6}{7}\)
_Học tốt_
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{7}{3\cdot3}\cdot\dfrac{3}{7\cdot5}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9}{11\cdot2}\cdot11\cdot5=\dfrac{45}{2}\)
\(\dfrac{11}{17}:\dfrac{33}{34}=\dfrac{11}{17}\cdot\dfrac{34}{33}=\dfrac{11\cdot17\cdot2}{17\cdot11\cdot3}=\dfrac{2}{3}\)
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
6 + y/33 = 7/11
y/33 = 7/11 - 6
y/33 = -59/11
y= -59/11 x 33
y= -177
=> Y/33= 7/11- 6= -59/ 11
=>Y= -59/11 . 33= -177
Vậy x= -177
Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
y/33=9/11-7
y/33=-68/11
y/33=-204/33
y=-204
y/33=9/11-7=-68/11
y= -68/11x 33=-2244/11= -204