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\(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)=49\dfrac{8}{23}-5\dfrac{7}{32}-14\dfrac{8}{23}=\left(49\dfrac{8}{23}-14\dfrac{8}{23}\right)-5\dfrac{7}{32}=35-5\dfrac{7}{32}=\dfrac{953}{32}\)
49. (-23 + 2.x) = (-49).(-23 + 14)
49. (-23 + 2.x) = (-49). (-9)
49. (-23 + 2.x) = 441
-23 + 2.x = 441 : 49
-23 + 2.x = 9
2.x = 9 - (-23)
2.x = 32
x = 32 : 2
x = 16
giải
49/8/23-(5/7/32+14/8/23)
=49/8/23-5/7/32-14/8/23
=(49/8/23-14/8/23)-5/7/32
=35-5/7/32
=953/32
1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)
\(=2155-174-2155-68+174\)
=-68
2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)
\(=-25\cdot\left(72-21+49\right)\)
\(=-25\cdot100=-2500\)
49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )
= \(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )
= \(\frac{1135}{23}\) - \(\frac{14401}{736}\)
=\(\frac{953}{32}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)
\(=\frac{1135}{23}.\frac{13665}{736}\)
\(=916,2201678\)
a/57x23+23x44-23
57x23+23x44-23x1
=23x(57+44-1)
=23x100
=2300
b
a) 57 . 23 + 23 . 44 - 23
= 57 . 23 + 23 . 44 - 23 . 1
= ( 57 + 44 - 1 ) . 23
= 100 . 23
= 2300
b) 1672 - [ 49 + ( 13 - 7 )3 ]
= 1672 - [ 49 + 63 ]
= 1672 - [ 49 + 216 ]
= 1672 - 265
= 1407
c) 50 : { 2 . [ 52 - ( 3 . 5 - 22 . 3 )3 ] }
= 50 : { 2 . [ 52 - ( 3 . 5 - 4 . 3 )3 ] }
= 50 : { 2 . [ 52 - ( 3 . 1 )3 ] }
= 50 : { 2 . [ 52 - 27 ] }
= 50 : { 2 . 25 }
= 50 : 50
= 1
d) -2014 + (-999) + 14 + (-2001)
= ( -2014 + 14 ) + [ (-999) + (-2001) ]
= (-2000) + (-3000)
= -5000
Học tốt nhé bạn !