Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
29\(\dfrac{1}{2}\)\(\times\)\(\dfrac{2}{3}\) + 39\(\dfrac{1}{3}\)\(\times\)\(\dfrac{3}{4}\) + \(\dfrac{5}{6}\)
= \(\dfrac{59}{2}\) \(\times\) \(\dfrac{2}{3}\) + \(\dfrac{118}{3}\) \(\times\) \(\dfrac{3}{4}\) + \(\dfrac{5}{6}\)
= \(\dfrac{59}{3}\) + \(\dfrac{59}{2}\) + \(\dfrac{5}{6}\)
= \(\dfrac{295}{6}\) + \(\dfrac{5}{6}\)
= 50
= 59/2 x 2/3+ 118/3 x 3/4 + 5/6
= 59/3+ 59/2+ 5/6
= 118/6+ 177/6+ 5/6
= 50
= 59/2 x 2/3+ 118/3 x 3/4 + 5/6
= 59/3+ 59/2+ 5/6
= 118/6+ 177/6+ 5/6
= 50
\(\dfrac{6}{x}+\dfrac{1}{2}=2\\ \dfrac{6}{x}=2-\dfrac{1}{2}\\ \dfrac{6}{x}=\dfrac{4}{2}-\dfrac{1}{2}\\ \dfrac{6}{x}=\dfrac{3}{2}\\ x=6:\dfrac{3}{2}\\ x=\dfrac{6x2}{3}\\ x=4\)
Đủ chi tiết chưa nhỉ ??
\(C=\dfrac{2}{5}+\dfrac{2}{45}+...+\dfrac{2}{6885}\)
\(=\dfrac{1}{2}\left(\dfrac{4}{1\cdot5}+\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}+...+\dfrac{4}{81\cdot85}\right)\)
\(=\dfrac{1}{2}\left(1-\dfrac{1}{85}\right)\)
\(=\dfrac{1}{2}\cdot\dfrac{84}{85}=\dfrac{42}{85}\)
\(1\dfrac{4}{5}+2\dfrac{5}{7}+3\dfrac{4}{5}+4\dfrac{5}{7}\)
\(\text{=}\left(1\dfrac{4}{5}+3\dfrac{4}{5}\right)+\left(2\dfrac{5}{7}+4\dfrac{5}{7}\right)\)
\(\text{=}1+3+\left(\dfrac{4}{5}+\dfrac{4}{5}\right)+2+4+\left(\dfrac{5}{7}+\dfrac{5}{7}\right)\)
\(\text{=}10+\dfrac{8}{5}+\dfrac{10}{7}\text{=}131\dfrac{1}{35}\)
x=39/32
x= 39/32 nha bn ^-^