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\(2x-3-3\cdot2x=-92\\\Rightarrow2x-3-6x=-92\\\Rightarrow2x-6x=-92+3\\\Rightarrow-4x=-89\\\Rightarrow x=-89:(-4)\\\Rightarrow x=\dfrac{89}{4}\)
2x – 3 – 3.2x = – 92.
2x-3-6x =-92
2x-6x =(-92)-3
2x-6x =-89
-4x =-89
x =(-89):(-4)
x =22.25
vậy x=22.25
2\(^{x-3}\) -3.2\(^x\) = -92
2\(^{x-3}\).(1 - 3.23) = (-92)
2\(^{x-3}\).(-23) = (-92)
2\(^{x-3}\) = (-92) : (-23)
2\(^{x-3}\) = 4
2\(^{x-3}\) = 22
\(x-3\) = 2
\(x\) = 2 + 3
\(x\) = 5
b) \(\left(x-3\right)^2=0,25\)
\(\Rightarrow\left(x-3\right)^2=\left(\pm0,5\right)^2\)
\(\Rightarrow x-3=\pm0,5.\)
\(\Rightarrow\left[{}\begin{matrix}x-3=0,5\\x-3=-0,5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0,5+3\\x=\left(-0,5\right)+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3,5\\x=2,5\end{matrix}\right.\)
Vậy \(x\in\left\{3,5;2,5\right\}.\)
c) \(\left(2x-1,5\right)^3=\left(-0,27\right)\) (câu này sai đề rồi nhé).
d) \(3.2x+\left(-1,2\right).x+2,7=\left(-4,9\right)\)
\(\Rightarrow3.2x+\left(-1,2\right).x=\left(-4,9\right)-2,7\)
\(\Rightarrow3.2x+\left(-1,2\right).x=-7,6\)
\(\Rightarrow6.x+\left(-1,2\right).x=-7,6\)
\(\Rightarrow\left[6+\left(-1,2\right)\right].x=-7,6\)
\(\Rightarrow4,8.x=-7,6\)
\(\Rightarrow x=\left(-7,6\right):4,8\)
\(\Rightarrow x=-\frac{19}{12}\)
Vậy \(x=-\frac{19}{12}.\)
Chúc bạn học tốt!
b) (x-3)\(^2\) = 0,25
(x-3)\(^2\) = (0,5)\(^2\)
x-3 = 0,5
x = 0,5 + 3
x = 0,8
a: =>\(4\cdot3^x\cdot\dfrac{1}{3}+2\cdot3^x\cdot9=4\cdot3^6+2\cdot3^9\)
=>3^x(4*1/3+2*9)=3^6(4+2*3^3)
=>3^x*58/3=3^6*58
=>3^x/3^6=3
=>x-6=1
=>x=7
b: =>\(2^x\cdot\left(\dfrac{1}{5}+\dfrac{1}{3}\cdot2\right)=2^7\left(\dfrac{1}{5}+\dfrac{1}{3}\cdot2\right)\)
=>2^x=2^7
=>x=7
\(3.2\times x\left(-1.2\right)\times x+2.7=-4.9\) câu a nhé
\(-5.6\times x+2.9\times x-3.86=-9.8\) câu b nhé
cảm ơn các bạn nhìu
3.2x+(-1.2)*x+2.7=-4.9
(3.2+(-1.2)*x=-4.9-2.7
2*x=-76
x=-76/2
x=-38
a: =>2x-1/3=2
=>2x=7/3
=>x=7/6
b: Sửa đề: 1/11-5/22
\(\dfrac{8}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{8}{9}:\dfrac{-3}{22}+\dfrac{5}{9}:\dfrac{-9}{15}\)
\(=\dfrac{8}{9}\cdot\dfrac{-22}{3}+\dfrac{5}{9}\cdot\dfrac{-5}{3}\)
\(=\dfrac{-66-25}{27}=\dfrac{-91}{27}\)
\(2^{x-2}-3.2^x=-88\)
\(2^x:2^2-2^x:\frac{1}{3}=-88\)
\(2^x:\left(2^2-\frac{1}{3}\right)=-88\)
\(2^x:\frac{11}{3}=-88\)
\(2^x=-88.\frac{11}{3}\)
\(2^x=\frac{-968}{3}\)
\(2^{x-2}-\)\(3.2^x=-88\)
\(2^x:2^2-2^x.3=-88\)
\(2^x.\frac{1}{4}-\)\(2^x.3=-88\)
\(2^x.\left(\frac{1}{4}-3\right)=-88\)
\(2^x.\frac{-11}{4}=-88\)
\(2^x=-88:\frac{-11}{4}\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(2^{x-2}-3.2^x=-88\)
\(\Rightarrow2^x:2^2-3.2^x=-88\)
\(\Rightarrow2^x.\left(\dfrac{1}{4}-3\right)=-88\)
\(\Rightarrow\)\(2^x.\left(-2\dfrac{3}{4}\right)=-88\)
\(\Rightarrow\)\(2^x=\)32
=> x=5
\(2^{x-2}-3.2^x=-88\)
\(2^x.2^{-2}-3.2x=-88\)
\(2^x.\left(2^{-2}-3\right)\) =-88
\(2^x.\left(\dfrac{1}{4}-3\right)\) =-88
\(2^x.\left(\dfrac{-11}{4}\right)\) =-88
\(2^x\) =\(-88:\left(\dfrac{-11}{4}\right)\)
\(2^x\) =32
\(2^x=2^5\)
\(\Rightarrow\) x=5