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2015 + 2015 x 2 + 2015 x 3 + 2015 x 4 = 2015 x ( 1 + 2 + 3 + 4 )
= 2015 x 10 = 20150
2015 x 23 + 55 x 2015 + 11 x 2015 x 2
= 2015 x (23 + 55 + 11 x 2)
= 2015 x (23 + 55 + 22)
= 2015 x (78 + 22)
= 2015 x 100
= 201500
\(2015x23+55x2015+11x2015x2\)
\(=2015x\left(23+55+11x2\right)\)
\(=2015x\left(23+55+22\right)\)
\(=2015x100\)
\(=201500\)
a/
\(\dfrac{4}{15}=1-\dfrac{11}{15}\)
\(\dfrac{5}{16}=1-\dfrac{11}{16}\)
\(\dfrac{11}{15}>\dfrac{11}{16}\Rightarrow1-\dfrac{11}{15}< 1-\dfrac{11}{16}\Rightarrow\dfrac{4}{15}< \dfrac{5}{16}\)
b/
\(\dfrac{2}{113}=\dfrac{4}{226}< \dfrac{4}{115}\)
c/ \(\dfrac{2}{7}=\dfrac{4}{14}< \dfrac{4}{9}\)
d/ \(\dfrac{2}{5}=\dfrac{4}{10}< \dfrac{4}{7}\)
a,\(\dfrac{4}{15}< \dfrac{5}{16}\)
b,\(\dfrac{2}{113}< \dfrac{4}{115}\)
c,\(\dfrac{2}{7}< \dfrac{4}{9}\)
d,\(\dfrac{4}{7}>\dfrac{2}{5}\)
Ta có: \(2015\cdot1\dfrac{3}{4}=2015\cdot\dfrac{7}{4}\)
( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 1 + 1/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 4/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x 0
=0
Ta có: \(\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
\(=\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(\dfrac{3}{3}+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
=0
1) 9 x 10 + 10 x 11 + 11 x 12 + ....+ 2015 x 2016
=9x10x11-8x9x10+10x11x12-9x10x11+...+2015x2016x2017-2014x2015x2013
=2015x2016x2017-8x9x10
=8193537360
= 2015 . ( 1+2+3+4)
=2015 . 10
= 20150