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mik ko ghi lại đề nhé!
\(A=\left(\frac{18}{15}.\frac{1}{4}.3\right)+\left(-\frac{47}{60}\right).\frac{24}{47}\)
\(A=\frac{8}{5}+\left(-\frac{2}{5}\right)\)
\(A=\frac{6}{5}\)
\(B=\frac{3}{4}.\frac{28}{15}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{24}{47}-\frac{17}{13}\)
\(B=\frac{7}{5}-\frac{47}{60}.\frac{24}{47}-\frac{17}{13}\)
\(B=\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(B=1-\frac{17}{13}\)
\(B=-\frac{4}{13}\)
THANKS
Câu 2 :
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)
\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(-\frac{4}{13}\)
mink không chép lại đề nha bạn
\(\dfrac{28}{15}\).\(\dfrac{3}{4}\)\(-\)\(\left(\dfrac{104}{195}+\dfrac{1}{4}\right).\dfrac{24}{47}-\dfrac{51}{13}:3\)
\(\dfrac{7}{5}\)\(-\dfrac{23}{60}\).\(\dfrac{24}{47}\)\(-\dfrac{17}{13}\)
\(\dfrac{7}{5}\)\(-\dfrac{46}{235}\)\(-\dfrac{17}{13}\)
\(\dfrac{283}{235}\)\(-\dfrac{17}{13}\)
= (đến đây bạn tự tính ra kết quả nhé)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{8}{15}+\dfrac{1}{4}\right)\cdot\dfrac{24}{47}-\dfrac{51}{13}\cdot\dfrac{1}{3}\\ =\dfrac{7}{5}-\dfrac{47}{60}\cdot\dfrac{24}{47}-\dfrac{17}{13}\\ =\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)
\(=1-\dfrac{17}{13}=-\dfrac{4}{13}\)
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{13}{12}:3\)
= \(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)
= \(\frac{4.3.7}{4.3.5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)
= \(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)
= \(1-\frac{49}{36}\)
= \(-\frac{13}{36}\)
Chúc bạn làm bài tốt
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{27}-3\frac{13}{12}:3\)
=\(\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)
=\(\frac{7}{5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)
=\(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)
=\(\frac{-13}{36}\)