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g. \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)
f. \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(\Leftrightarrow x\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{12}\)
\(\Leftrightarrow x\left(\frac{4}{6}-\frac{3}{6}\right)=\frac{5}{12}\)
\(\Leftrightarrow\frac{1}{6}x=\frac{5}{12}\)
\(\Leftrightarrow x=\frac{5}{12}\div\frac{1}{6}\)
\(\Leftrightarrow x=\frac{30}{12}=\frac{5}{2}\)
a) 2. |1/2-1/3| - 3/2 =1/4 b)3/4-2.|2x-3/2|=2
2.|1/2-1/3|=1/4+3/2 2|2x-3/2|=3/4-2
2.|1/2-1/3|=2/8+12/8 2|2x-3/2|=-5/4
2.|1/2x-1/3|=14/8 |2x-3/2|=-5/4:2
|1/2x-1/3|=14/8:2 |2x-3/2|=-5/8
1/2x-1/3=14/8.2/1 x-3/2=-5/8:2
1/2x-1/3=14/4 x-3/2=-5/16
x-1/3=14/4:1/2 x=-5/16+3/2
x-1/3=14/4.2 x=19/16
x-1/3=7 => x= 19/16 hoặc -19/16
x=7+1/3
x=21/3+1/3
x=22/3
=>x= 22/3 hoăc -22/3
c
\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right)......\left(1+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3}{1.3}+\frac{1}{1.3}\right).\left(\frac{2.4}{2.4}+\frac{1}{2.4}\right).....\left(\frac{2016.2018}{2016.2018}+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3+1}{1.3}\right).\left(\frac{2.4+1}{2.4}\right).....\left(\frac{2016.2018+1}{2016.2018}\right)\)
\(=\frac{4}{1.3}.\frac{9}{2.4}.....\frac{4068289}{2016.2018}=\frac{2^2}{1.3}.\frac{3^2}{2.4}....\frac{2017^2}{2016.2018}\)
\(=\frac{2^2.3^2.....2017^2}{1.3.2.4.....2016.2018}=\frac{2.2.3.3.4.4...2017.2017}{1.3.2.4.....2016.2018}=\frac{\left(2.3.4.....2017\right).\left(2.3.4..2017\right)}{\left(1.2....2016\right).\left(3.4....2018\right)}\)
\(=\frac{2017.2}{1.2018}=\frac{4034}{2018}\)
12x+3.23=23.x-4.32
12x+3.8=8.x-4.9
12x+24=8x-36
12x-8x=36-24
4x=12
x=12:4=3
a ) 1/3x + 2/5 ( x - 1 ) = 0
1/3x + 2/5x - 2/5 = 0
x . ( 1/3 + 2/5 ) = 2/5
x . 11/15 = 2/5
=> x = 6/11
Vậy x = 6/11
\(\frac{4}{3}B=-1+\frac{3}{4}-\left(\frac{3}{4}\right)^2+...+\left(\frac{3}{4}\right)^{99}\)
\(B=-\frac{3}{4}+\left(\frac{3}{4}\right)^2-\left(\frac{3}{4}\right)^3+...+\left(\frac{3}{4}\right)^{100}\)
\(\Rightarrow\)\(\frac{7}{3}B=-1+\left(\frac{3}{4}\right)^{100}\Rightarrow B=\frac{\left(\frac{3}{4}\right)^{100}-1}{\frac{7}{3}}=\frac{3\left[\left(\frac{3}{4}\right)^{100}-1\right]}{7}\)
Như vầy đủ gọn chưa bạn?
1/4 + 1/3 : (2x - 1) = -5
=> 1/3 : (2x - 1) = -21/4
=> 2x - 1 = -63/4
=> 2x = -59/4
=> x = -59/8
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\frac{1}{3}:\left(2x-1\right)=\left(-5\right)-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=\frac{-21}{4}\)
\(2x-1=\frac{1}{3}:\frac{-21}{4}\)
\(2x-1=\frac{-4}{63}\)
\(2x=\frac{-4}{63}+1\)
\(2x=\frac{59}{63}\)
\(x=\frac{59}{63}:2\)
\(x=\frac{59}{126}\)