Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a ) cách 1 :
\(8.25.\left(-125\right)+4.12.\left(-20025\right)^0:\left(-3\right)\)
\(=\left(-125.8\right).\left(4.25\right).12.1:\left(-3\right)\)
\(=\left(-1000\right).100.12\)
\(=-1200000:\left(-3\right)\)
\(=400000\)
a) cách 2 :
\(..............\)
\(=\left(8.25\right)\left(-125.4\right).12.1:\left(-3\right)\)
\(=200.\left(-500\right).12:\left(-3\right)\)
\(=-1200000:\left(-3\right)=400000\)
a)35-(12-(-14+(-2)))
=35-(12-(-12))
=35-(12+12)
=35-24
=11
b)49-(-54)-23
=49+54-23
=103-23
=80
c)5871:(928-((-82)+247))×5)
=5871:(928-165×5)
=5871:(928-825)
=5871:103
=57
d) 135(-12 + 247) - 147(135 - 12)= -12.135 + 135.147 - 147.135 + 12.147 = (-12.135 + 12.147) + (135.147 - 147.135) = 12(-135 + 147) + 0 = -12.12 = -144
Bài 1:
a) [3.(-2) - (-8)].(-7) - (-2).(-5) = -7(-6 + 8) - 2.5= -7.2 - 2.5 = -2(7 + 5) = -2.12 = -24
25x26+75x|-24|
=25x26+75x24
=25x24+25x2+75x24
=(25+75)x24 + 25x2
=100x24+100
=2400+100
=2500
a) \(\left(-25\right).5.\left(-4\right).2\)
\(=\left[\left(-25\right).\left(-4\right)\right].\left(2.5\right)\)
\(=100.10=1000\)
b) \(\left(-456\right)-\left(67-456\right)\)
\(=-456-67+456\)
\(=\left(456-456\right)-67\)
\(=67\)
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
1. 125-125+39+11
=50
2. 39.46+30.(-61)-39.76
=1794 + (-1830) -2964
= -3000
3. -195.56-43.195-195
= -10920 - 8385 - 195
= -19500
mk lm nửa thôi nhé bn vì bh mik có vc bận r