viết bài văn kể lại một trải nghiệm đáng nhớ của em ( một chuyến đi đáng nhớ) 20 đến 25 câu
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1. Sports and games are very important in out lives.
2. Television programmes about sports are also very popular.
3. The Olympic Games first took place in Greece in 776 BC.
4. Try to get up early and do some exercise.
5. He became the world tennis champion when he was very young.
6. Don't use the lift when there is fire.
7. What equipment do you need to play the sport?
8. Mai will meet Duong at Superfit Club on Sunday.
1. very/and/are/our/important/games/lives./in/Sports
Sports and games are very important in our lives
2. Television/very/about/popular./sports/programmes/also/are
Television programmes about sports are also very popular
3. first/in/place/ Greece/ BC/776/in/ The Olympic Games/took/.
The Olympic Games first took place in Greece in 776 BC
4. get/to/ Try/exercise/ do/ some/early/up/to/>
Try to get up early to do some exercise
5. became when/ the/young/ world tennis/ He/ was/ very/he
He became the world tennis when he was very young
6. use/ the lift/ when/fire./ Don't/ is/ there =>
Don't use the lift when there is fire
7.do/you/the/equipment/ sport?/play/What/to/need
What equipment do you need to play sport?
8. Mai//meet/Superfit/on/Club/and/will/at/Duong/Sunday.
Mai will meet Duong at Superfit club on Sunday
Câu 8 Vải sợi tổng hợp thuộc loại vải nào A. Vải sợi thiên nhiên B. Vải sợi hóa học C. Vải sợi pha D. Không thuộc đáp án trên .
- Biện pháp tu từ : So sánh
" Bóng Bác cao lồng lộng,
Ấm hơn ngọn lửa hồng"
=> Tác dụng : Điểm tô đậm đà hình ảnh vị lãnh tụ tối cao của dân tộc lớn lao, vĩ đại. Bác hiện lên rõ nét và thật vĩ đại , là tâm điểm của bức tranh phác hoạ màn đêm trong chiến dịch biên giới năm 1950.
Hiệu vận tốc của 2 xe là:
12-11=1 (km/giờ)
Hai xe gặp nhau sau thời gian là:
7:1=7 (giờ)
Hai xe gặp nhau lúc:
7 giờ + 7 giờ = 14 giờ
Chỗ gặp nhau cách A là:
12.7=84 (km)
Đáp số: 2 xe gặp nhau lúc 14 giờ và chỗ gặp nhau cách A 84 km
\(\dfrac{5}{13}\cdot\dfrac{-3}{10}\cdot\dfrac{-3}{5}\)
\(=\dfrac{5}{5}\cdot\dfrac{-3}{13}\cdot\dfrac{-3}{10}\)
\(=\dfrac{3}{13}\cdot\dfrac{3}{10}=\dfrac{9}{130}\)
\(\dfrac{3}{4}\cdot\dfrac{1}{13}-\dfrac{3}{4}\cdot\dfrac{14}{13}\)
\(=\dfrac{3}{4}\left(\dfrac{1}{13}-\dfrac{14}{13}\right)\)
\(=\dfrac{3}{4}\cdot\dfrac{-13}{13}=-\dfrac{3}{4}\)
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