Phân tích Đa thức thành nhân tử
1)3x^3-12x
2)x^3+x^2 - x -1
X^2 -7xy+10y^2
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x^2 - 7xy + 10y^2
= (x^2 - 2xy) - (5xy - 10y^2)
= x(x - 2y) - 5y( x - 2y)
= (x - 5y)(x - 2y)
= x^2 - 7xy + 10y^2
= x^2 - 2xy -5xy + 10y^2
= x( x - 2y ) - 5y( x - 2y )
= ( x - 2y )( x - 5y )
\(a,x^2\left(x-2\right)-4x+8\\ =\left(x^2-4\right)\left(x-2\right)\\ =\left(x-2\right)^2\left(x+2\right)\\ b,x^2+7xy+10y^2\\ =x^2+2xy+5xy+10y^2\\ =x\left(x+2y\right)+5y\left(x+2y\right)\\ =\left(x+5y\right)\left(x+2y\right)\)
\(x^2+4x-y^2+4\)
\(=\left(x^2+4x+4\right)-y^2\)
\(=\left(x^2+2\right)^2-y^4\)
\(=\left(x^2+y^2+2\right)\left(x^2-y^2+2\right)\)
\(\left(x^2+4x+4\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
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hk tôt
1) \(3x^3-12x\)
\(=3x\left(x^2-4\right)\)
\(=3x\left(x+2\right)\left(x-2\right)\)
2)\(x^3+x^2-x-1\)
\(=\left(x^3+x^2\right)-\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-1\right)\)
\(=\left(x+1\right)^2\left(x-1\right)\)
3) \(x^2-7xy+10y^2\)
\(=\left(x^2-2xy\right)-\left(5xy-10y^2\right)\)
\(=x\left(x-2y\right)-5y\left(x-2y\right)\)
\(=\left(x-5y\right)\left(x-2y\right)\)
1) \(3x^3-12x\)
\(=3x\left(x^2-4\right)\)
\(=3x\left(x-2\right)\left(x+2\right)\)
2) \(x^3+x^2-x-1\)
\(=x^2\left(x+1\right)-\left(x+1\right)\)
\(=\left(x^2-1\right)\left(x+1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(x+1\right)\)