Tìm X
125 + ( X - 25) x 5 + X =150
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4 × 125 × 25 × 8
= (4 × 25) × (125 × 8)
= 100 × 1000
= 100 000
2 × 8 × 50 × 25 × 125
= (2 × 50) × (8 × 125) × 25
= 100 × 1000 × 125
= 12 500 000
2 × 3 × 4 × 5 × 50 × 25
= (2 × 50) × (4 × 25) × (3 × 5)
= 100 × 100 × 15
= 150 000
25 × 20 × 125 × 8 - 8 × 20 × 5 × 125
= 8 × 125 × 20 × (25 - 5)
= 1000 × 20 × 20
= 400 000
- (25 x 4) x (125 x8)=100 x 1000 =100000
- (50 x 2) x (8 x 125) x 25=100 x 1000 x 25 =2500000
- (2 x 50 ) x (4 x 25) x (3 x5)=100 x 100 x 15=150000
- 25 x 20 x125 x 8 - 5
= (20 x 5) x (125 x 8) -25=100 x 1000 -5 =100000 - 5 =99995
a) \(x.125=32250\)
\(x=32250:125\)
\(x=258\)
b) \(39975:x=123\)
\(x=39975:123\)
\(x=325\)
\(x\times125=32250\)
\(\Rightarrow x=258\)
_____
\(39975:x=123\)
\(\Rightarrow x=325\)
a, 2 x 7,65 x 5
= ( 2 x 5 ) x 7,65
= 10 x 7,65
= 76,5
b, 25 x 1,9 x 4
= ( 25 x 4 ) x 1,9
= 100 x 1,9
= 190
c , 6,92 x 8 x 125
= 6,92 x ( 125 x8 )
= 6,92 x 1000
= 6920
d, 15,7 x 8 + 15,7 x2
= 15,7 x ( 8 + 2 )
= 15,7 x 10
= 157
\(\left(x+5\right)+\left(x+10\right)+...+\left(x+25\right)-125=150\)
\(\Leftrightarrow x+5+x+10+...+x+25-125=150\)
\(\Leftrightarrow5x-50=150\)
\(\Leftrightarrow5x=100\)
\(\Leftrightarrow x=\dfrac{100}{5}=20\)
Vậy \(x=20\)
\(\frac{120\times999+120}{2\times4\times0,8\times5\times2,5\times125}\)
\(=\frac{120\times1000}{\left(125\times0,8\right)\left(4\times2,5\right)\left(2\times5\right)}\)
\(=\frac{120000}{100\times10\times10}\)
\(=\frac{120000}{10000}\)
\(=\frac{12}{1}=12\)
1. \(\Leftrightarrow\frac{59-x}{41}+1+\frac{57-x}{43}+1+\frac{55-x}{45}+1+\frac{51-x}{49}+1=-5+5\)
\(\Leftrightarrow\frac{100-x}{41}+\frac{100-x}{43}+\frac{100-x}{45}+\frac{100-x}{47}+\frac{100-x}{49}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\frac{1}{41}+\frac{1}{43}+\frac{1}{45}+\frac{1}{47}+\frac{1}{49}\right)=0\)
\(\Leftrightarrow x-100=0\Leftrightarrow x=100\)
2. \(\Leftrightarrow\frac{x-5}{1990}+1+\frac{x-15}{1980}+1+\frac{x-25}{1970}=\frac{x-1990}{5}+1+\frac{x-1980}{15}+1+\frac{x-1970}{25}+1\)
\(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}=\frac{x-1995}{5}+\frac{x-1995}{15}+\frac{x-1995}{25}\)
\(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}-\frac{x-1995}{5}-\frac{x-1995}{15}-\frac{x-1995}{25}=0\)
\(\Leftrightarrow\left(x-1995\right)\left(\frac{1}{1990}+\frac{1}{1980}+\frac{1}{1970}-\frac{1}{5}-\frac{1}{15}-\frac{1}{25}\right)=0\)
\(\Leftrightarrow x-1995=0\Leftrightarrow x=1995\)
125 + ( X - 25) x 5 + X = 150
( X - 25) x 5 + X = 150 - 125
( X - 25) x 5 + X = 25
Suy ra : (X - 25) + X = 25 : 5
= (X - 25) + X = 5
X - 25 + X = 5
Vậy X = 25 - 5
Tương ứng với X = 20
125+(X-25)*5+X=150
125+X*5-25*5+X=150
125+X*5-125+X=150
X*6=150
X=150/6
X=25