tìm x: | x + 2 | + x = 0
ai nhanh đúng mk tk
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\(78-\left(x-25\right).3\frac{1}{3}=73\)
\(78-\left(x-25\right)\cdot\frac{10}{3}=73\)
\(\left(x-25\right)\cdot\frac{10}{3}=78-73\)
\(\left(x-25\right)\cdot\frac{10}{3}=5\)
\(x-25=5:\frac{10}{3}\)
\(x-25=1,5\)
\(x=25+1,5=26,5\)
Tìm x :
2,8 : x - 1,5 = 2,3 : 5,75
=> x - 1,5 = 5,75
x = 5,75 + 1,5
x = 7,25
Tính nhanh :
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{13\times14}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{13}-\frac{1}{14}\)
\(=1-\frac{1}{14}+0+...+0\)
\(=\frac{13}{14}\)
1. 2,8 : x - 1,5 = 2,3 : 5,75
2,8 : x - 1,5 = 0,4
2,8 : x = 0,4 + 1,5
2,8 : x = 1,9
x = 2,8 : 1,9
x = 1,473
2. \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{13.14}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{13}-\frac{1}{14}\)
= \(1-\frac{1}{14}\)
= \(\frac{13}{14}\)
x+13425475=35346897957967567
x= 35346897957967567-13425475
x=35346897944542092
---------------------------------------------------------
x+567342002=1234235748697582
x=1234235748697582-567342002
x=1234235181355580
x + 13425475 = 35346897957967567
x = 35346897957967567 - 13425475
x = 3534689782542092
x + 567342002 = 1234235748697582
x = 1234235748697582 - 567342002
x = 1234253181355580
Ta có \(\frac{3}{2}-\frac{5}{2}.\left(1,2x-3\right)^2=-0,9\)
\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{3}{2}+0,9\)
\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{21}{2}\)
\(\Rightarrow\left(1,2x-3\right)^2=\frac{21}{5}\)
đề sai hay mình sai ????
a) 35 x 34 + 35 x 38 + 65 x 75 + 65 x 45
= 35 x (34+38) + 65 x (75 + 45)
= 35 x 72 + 65 x 120
= 2520 + 7800 = 10320
b) 3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12
= 3 x ( 25 x 8) + 4 x (37 x 6) + 2 x (38 x 12)
= 3 x 200 + 4 x 222 + 2 x 456
= 600 + 888 + 912 = 2400
tk nha
35 x 34 + 35 x 38 + 65 x 75 + 65 x 45
= 35 x ( 34 + 38 ) + 65 x ( 45 + 75 )
= 35 x 72 + 65 x 120
x=-1 hh
vì -1+2=1
1+(-1)=0
=> x= -1
Khi \(x\ge-2\)
\(x+2+x=0\Leftrightarrow x=-1\)(nhận)
Khi \(x< -2\)
\(-x-2+x=0\Leftrightarrow-2=0\)(vô lý)
Vậy x = -1.