5^x 2=1 help me please
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(5^{x+2}-5^x=3.10^3\)
\(\Rightarrow5^x\left(5^2-1\right)=3000\)
\(\Rightarrow5^x.24=3000\Rightarrow5^x=125=5^3\)
\(\Rightarrow x=3\)
\(5^{x+2}-5^x=3\cdot10^3\)
\(\Leftrightarrow5^x\cdot24=3000\)
\(\Leftrightarrow x=3\)
\(\dfrac{1}{5}\left(x+\dfrac{1}{5}\right)+\dfrac{2}{5}\left(x+\dfrac{5}{3}\right)=\dfrac{98}{75}\\ =>\dfrac{1}{5}x+\dfrac{1}{25}+\dfrac{2}{5}x+\dfrac{2}{3}=\dfrac{98}{75}\\ =>\dfrac{3}{5}x=\dfrac{98}{75}-\dfrac{2}{3}-\dfrac{1}{25}=\dfrac{3}{5}\\ =>x=1\)
\(\dfrac{1}{5}\left(x+\dfrac{1}{5}\right)+\dfrac{2}{5}\left(x+\dfrac{5}{3}\right)=\dfrac{98}{75}\\ \Rightarrow\dfrac{1}{5}x+\dfrac{1}{25}+\dfrac{2}{5}x+\dfrac{2}{3}=\dfrac{98}{75}\\ \Rightarrow\left(\dfrac{1}{5}x+\dfrac{2}{5}x\right)+\left(\dfrac{1}{25}+\dfrac{2}{3}\right)=\dfrac{98}{75}\\ \Rightarrow\dfrac{3}{5}x+\dfrac{53}{75}=\dfrac{98}{75}\\ \Rightarrow\dfrac{3}{5}x=\dfrac{98}{75}-\dfrac{53}{75}\\ \Rightarrow\dfrac{3}{5}x=\dfrac{45}{75}=\dfrac{3}{5}\\ \Rightarrow x=\dfrac{3}{5}:\dfrac{3}{5}\\ \Rightarrow x=1\)
\(\dfrac{5}{7}< \dfrac{x}{5}< 1\)
\(\dfrac{5\times5}{7\times5}< \dfrac{7\times x}{7\times5}< \dfrac{35}{35}\)
\(\dfrac{25}{35}< \dfrac{7\times x}{35}< \dfrac{35}{35}\)
\(25< 7\times x< 35\)
\(\dfrac{25}{7}< x< \dfrac{35}{7}\)
\(\dfrac{25}{7}< x< 5\)
\(3< x< 5\) (x is the natural number)
x=4
a: \(=\dfrac{7}{5}\cdot\dfrac{15}{49}-\dfrac{12+10}{15}:\dfrac{11}{5}\)
\(=\dfrac{3}{7}-\dfrac{22}{15}\cdot\dfrac{5}{11}=\dfrac{3}{7}-\dfrac{2}{3}=\dfrac{9-14}{21}=\dfrac{-5}{21}\)
b: =>2,8x-32=-60
=>2,8x=-28
hay x=-10
/x+5/+/x-1/=12:/y+5/+3
suy ra x+5+x-1=12:/y+5/+3 hoặc x+5+x-1=12:-<y+5>+3
\(2^x+2^{x-1}+2^{x-2}=2^{x-2}.2^2+2^{x-2}.2+2^{x-2}\)\(=2^{x-2}\left(4+2+1\right)=2^{x-2}.7\)
thank you
(x – 2) – (39 – 45) = | - 5| - | -10|
(x - 2) - 6 = 5 - 10
(x - 2) - 6 = - 5
x - 2 = - 5 + 6
x - 2 = 1
x = 1 + 2
x = 3
Vậy x = 3
\(\left(x-2\right)+6=-5\)
\(\Rightarrow x-2=-11\)
\(\Rightarrow x=-9\)
Ta có: \(|-x-5|=|1-5|\)
<=> \(|-x-5|=4\)
<=>\(\orbr{\begin{cases}x-5=4\\x-5=-4\end{cases}}\)
<=>\(\orbr{\begin{cases}x=9\\x=1\end{cases}}\)
Vậy x=1 hoặc x=9
có thiếu dấu ko ạ ?
ko nha năm mũ x cộng 2 = 1 đúng