Nhap N so bat ki tu ban phim , dem cac so lon hon 10 va nho hon 20 va thong bao ket qua ra man hinh (Trong chuong trinh c++)
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uses crt;
var diem:real;
begin
clrscr;
write('nhap diem:'); readln(diem);
if diem<5 then writeln('ban can co gang hon');
if (diem>=5) and (diem<6.5) then writeln('ban dat diem trung binh');
if (diem>=6.5) and (diem<8) then writeln('ban dat diem kha');
if diem>=8 then writeln('ban dat diem gioi');
readln;
end.
uses crt;
var a:array[1..100]of integer;
i,n,t:integer;
begin
clrscr;
write('n='); readln(n);
if (n>0) and (n<=100) then
begin
t:=0;
for i:=1 to n do
begin
write('a[',i,']='); readln(a[i]);
if (a[i] mod 2=0) or (a[i] mod 2=1) then t:=t+a[i];
end;
writeln('tong cac phan tu chan hoac le trong day la: ',t);
end
else writeln('vui long nhap lai');
readln;
end.
#include <bits/stdc++.h>
using namespace std;
double a,b;
int main()
{
cin>>a>>b;
cout<<"a truoc khi doi la:"<<fixed<<setprecision(2)<<a<<endl;
cout<<"b truoc khi doi la:"<<fixed<<setprecision(2)<<b<<endl;
swap(a,b);
cout<<"a sau khi doi la:"<<fixed<<setprecision(2)<<a<<endl;
cout<<"b sau khi doi la:"<<fixed<<setprecision(2)<<b;
return 0;
}
Lời giải :
program hotrotinhoc ;
var a: array[1..32000] of integer ;
i,n,max : integer ;
begin
write('Nhap n='); readln(n);
writeln('Nhap gia tri cua cac phan tu');
for i:= 1 to n do
begin
write('a[',i,']='); readln(a[i]);
end;
max:=a[1];
for i:= 1 to n do if max<a[i] then max:=a[i];
write('So lon nhat la:',max');
readln
end.
uses crt;
var j,tg,s,max,min,i,n:longint;
a:array[1..19] of longint;
s1:real;
begin
clrscr;
write('Nhap n: '); readln(n);
for i:=1 to n do
begin
write('a[',i,']=');readln(a[i]);
end;
for i:=1 to n-1 do
for j:=i+1 to n do
if a[i]>a[j] then
begin
tg:=a[i];
a[i]:=a[j];
a[j]:=tg;
end;
for i:=1 to n do
write(a[i],' ');writeln;
for i:=1 to n do
s:=s+a[i];
s1:=s/n;
writeln(‘Gia tri trung binh cua cac phan tu la: ‘,s1:0:0);
min:=a[1];max:=a[1];
for i:=2 to n do begin
if a[i]>max then max:=a[i];
if a[i]<min then min:=a[i];
write('Phan tu lon nhat la: ',max,' ','Phan tu nho nhat la: ',min); writeln;
for i:=1 to n do
if (a[i]<>0) and (a[i] mod 2=0) then write(a[i],' ');
readln
end.
uses crt;
var X:string;
demtu,demdc,i:word;
begin
clrscr;
write('nhap cau van X:');readln(X);
writeln('so ki tu la:',length(X));
demtu:=1;
for i:=1 to length(X)-1 do
if (X[i]<>' ') and (X[i+1]=' ') then demtu:=demtu+1;
writeln('so tu la:',demtu);
demdc:=0;
for i:=1 to length(X) do
if X[i]=' ' then demdc:=demdc+1;
writeln('so dau cach la:',demdc);
readln;
end.
bài này mới đúng nè bạn:
uses crt;
var X:string;
demtu,demdc,i:word;
begin
clrscr;
write('nhap cau van X:');readln(X);
writeln('so ki tu la:',length(X));
X:=X+' ';
demtu:=0;
for i:=1 to length(X)-1 do
if (X[i]<>' ') and (X[i+1]=' ') then demtu:=demtu+1;
writeln('so tu la:',demtu);
delete(X,length(X),1);
demdc:=0;
for i:=1 to length(X) do
if X[i]=' ' then demdc:=demdc+1;
writeln('so dau cach la:',demdc);
readln;
end.
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdio>
using namespace std;
#include <bits/stdc++.h>
int main() {
int n;
cin >> n;
int total = 0;
for (int i = 1; i <= n; i++) {
if (i % 20 == 0 && i % 10 != 0) {
if (i <= (n / 10)) {
total += i * i;
}
} else {
total += i;
}
}
cout << "The total is: " << total << endl;
for (int i = 0; i < n; i++) {
int du = i % 10;
int tongcacso = i % 10 * i % 10 * i % 10;
cout << "du = " << du << endl;
total += du * du * du;
cout << "\nsum = " << total << endl;
cout << "sum = (sum+i*i*i) " << endl;
}
return 0;
}