1 + 2 + 3 + 4 + 5 + ... + 1000. Tính tổng
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\(\frac{999}{1000}+\frac{998}{1000}+......+\frac{1}{1000}\)
\(=\frac{999+998+997+........+1}{1000}\)
\(=\frac{499500}{1000}=\frac{999}{2}\)
1/1000 + ... + 997/1000 + 998/1000 + 999/1000 = ( 1 + ... + 997 + 998 + 999 ) / 1000 = 499500/1000 = 4995/10
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\(\frac{2}{3}+\frac{1}{3}=1=\frac{2}{2}\)
\(\frac{3}{4}+\frac{2}{4}+\frac{1}{4}=\frac{6}{4}=\frac{3}{2}\);
\(\frac{4}{5}+\frac{3}{5}+\frac{2}{5}+\frac{1}{5}=2=\frac{4}{2}\)
;\(\frac{5}{6}+\frac{4}{6}+\frac{3}{6}+\frac{2}{6}+\frac{1}{6}=\frac{15}{6}=\frac{5}{2}\)
Tổng quát:
\(\frac{n-1}{n}+\frac{n-2}{n}+...+\frac{2}{n}+\frac{1}{n}\)(\(n\in N\)) \(=\frac{n-1}{2}\)
Áp dụng:
\(\frac{999}{1000}+\frac{998}{1000}+\frac{997}{1000}+...+\frac{1}{1000}=\frac{999}{2}\).
Xem bài mình đúng không?
Bx3=1x3/1x2x3x4+1x3/2x3x4x5+...+1x3/97x98x99x100
Bx3=3/1x2x3x4+3/2x3x4x5+...+3/97x98x99x100
Bx3=1/1x2x3-1/2x3x4+1/2x3x4-1/3x4x5+...+1/97x98x99-1/98x99x100
BX3=1/1x2x3-1/98x99x100
BX3=1/6-1/970200
Bx3=161700/970200-1/970200
Bx3=161399/970200
B=161699/970200:3
B=161699/970200x1/3
B=161699/2910600
\(B=\frac{1}{1.2.3.4}+\frac{1}{2.3.4.5}+....+\frac{1}{97.98.99.100}\)
\(B=\frac{4-1}{1.2.3.4}+\frac{5-2}{2.3.4.5}+...+\frac{100-97}{97.98.99.100}\)
\(B=\frac{1}{3}\cdot\left(\frac{1}{1.2.3}-\frac{1}{2.3.4}+\frac{1}{2.3.4}-\frac{1}{3.4.5}+...+\frac{1}{97.98.99}-\frac{1}{98.99.100}\right)\)
\(B=\frac{1}{3}\cdot\left(\frac{1}{1.2.3}-\frac{1}{98.99.100}\right)\)
\(B=\frac{1}{3}\cdot\frac{161699}{970200}=\frac{161699}{2910600}\)
A=1+2+3+4+5+6+7....+1000
=(1+1000)+(2+999)+...+(500+501)
=1001+1001+...+1001
=1001x500
=500500
Tổng của dãy số trên là:
(1+1000)x1000:2=500500
Đáp số:500500
Ai thấy đúng thì tk mk nha
= 1001001