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Ta có : (1+2+3+.....+100).(12+ 22 +.....+102 ).(65.111 - 13.15.37)
=A .B.(65.111-13.5.3.37)
=A.B.(65.111-65.111)
=A.B.0
=0
B=C*[13*37*(5*3-15)]=0
\(A=\dfrac{2^{10}\cdot78}{2^8\cdot26\cdot4}=\dfrac{78}{26}=3\)
a, 48.84
= (22)8.(23)4
= 216.212
= 228
b, 415.515
= (4.5)15
= 2015
c, 210.15 + 210.85
= 210.(15 + 85)
= 210.100
=210.(2.5)2
= 212.52
d, 33.92
= 33 . (32)2
= 33.34
= 37
e, 512.7 - 511.10
= 511.(5.7 - 10)
= 511.25
=511.52
=513
f, \(x^1\).\(x^2\).\(x^3\)....\(x^{100}\)
= \(x^{1+2+3+...+100}\)
= \(x^{\left(1+100\right).100:2}\)
= \(x^{5050}\)
b, ( mik cx ko viết đề bài lun ^_^ )
= ( 1 + 2 + 3 + ... + 100 ) . ( 12 + 22 + 32 + ... + 102 ) . ( 65 . 111 - 13 . 555 )
= ( 1 + 2 + 3 + ... + 100 ) . ( 12 + 22 + 32 + ... + 102 ) . ( 65 . 111 - 13 . 5 . 111 )
= ( 1 + 2 + 3 + ... + 100 ) . ( 12 + 22 + 32 + ... + 102 ) . ( 65 . 111 - 65 . 111 )
= ( 1 + 2 + 3 + ... + 100 ) . ( 12 + 22 + 32 + ... + 102 ) . 0
= 0
Chúc hok tốt !
Mk nhầm sr nhé :
A = \(\frac{2^{10}\left(13+65\right)}{2^8.2^3.13}\)
A = \(\frac{2^{10}.78}{2^{11}.13}\)
A = \(\frac{2^{10}.13.3.2}{2^{11}.13}\)
A = \(\frac{2^{11}.13.3}{2^{11}.13}\)
A = \(3\)
c) \(\left(\dfrac{5}{4}\right)^4:\left(\dfrac{15}{2}\right)^4=\left(\dfrac{5}{4}:\dfrac{15}{2}\right)^4=\left(\dfrac{1}{6}\right)^4\)
d) \(10^4:16=10^4:2^4=\left(10:2\right)^4=5^4\)
e) \(\left(-2\right)^3.125=\left(-2\right)^3.5^3=\left(-2.5\right)^3=-10^3\)
f) \(64^3:\left(-2\right)^9=64^3:\left(-8\right)^3=\left(64:-8\right)^3=-8^3\)
