tính hợp lý
A=(22/1.3).(32/2.4)....(9992/998.10000
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{2^2}{1\times3}\times\dfrac{3^2}{2.4}\times\dfrac{4^2}{3.5}\times\dfrac{5^2}{4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.3.2.4.3.5.4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.2.3.3.4.4.5.2.3}=\dfrac{2^2.3^2.4^2.5^2}{3^3.2^2.4^2.5.1}=\dfrac{5}{3.1}=\dfrac{5}{3}\)
\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot\dfrac{5^2}{4.6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot2\cdot4^2\cdot4^2\cdot5\cdot6}\\ =\dfrac{2\cdot5}{6}=\dfrac{5}{3}\)
\(A=\frac{2^2}{1.3}\cdot\frac{3^2}{2.4}....\frac{999^2}{998.1000}\)
\(A=\frac{2^2.3^2....999^2}{1.3.2.4.998.100}=\frac{\left(2.3.....999\right)\left(2.3....999\right)}{\left(1.2....998\right)\left(3.4....1000\right)}\)
\(A=999\cdot\frac{1}{500}=\frac{999}{500}\)( khúc này mk làm tắt, bn bỏ dấu ở trên rồi bỏ từng tử)
=?????????????????????????????????????????????????????????????????????????????????????????????????????????????????
a: \(274+351+126-151\)
\(=274+126+351-151\)
=400+200
=600
b: \(5^7:5^5\cdot3\cdot7\cdot4\)
\(=5^2\cdot21\cdot4\)
\(=21\cdot100=2100\)
c: \(164\cdot27+164\cdot73-400\)
\(=164\left(27+73\right)-400\)
=16400-400
=16000
d: \(300-2\cdot\left[\left(6^2-32\right):2^2+99\right]\)
\(=300-2\left[\dfrac{\left(36-32\right)}{4}+99\right]\)
=300-200
=100
= 1.( 2 + 1 ) + 2 ( 3 + 1 ) + 3( 4 + 1 ) + ..... + 98( 99 + 1 )
= 1 . 2 + 1 + 2 . 3 + 2 + 3 . 4 + 3 + ...... 98 . 99 + 98
= ( 1 . 2 + 2 . 3 + 3 . 4 + ..... + 98 . 99 ) + ( 1 + 2 + 3 + ..... + 98 )
= 323400 + 4851
= 328351
Ta có :
\(A=\frac{2^2}{1.3}.\frac{3^2}{2.4}.....\frac{999^2}{998.1000}\)
\(A=\frac{2.2}{1.3}.\frac{3.3}{2.4}.....\frac{999.999}{998.1000}\)
\(A=\frac{2.3.....999}{1.2.....998}.\frac{2.3.....999}{3.4.....1000}\)
\(A=999.\frac{2}{1000}\)
\(A=\frac{999}{500}\)
éo phải
nu