\(\frac{x}{125}\)=\(\frac{69}{115}\)
Tìm x là :.......
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x:125=\(\frac{69}{115}\)
x=\(\frac{69}{115}\times125\)
x=75
\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)
\(\Leftrightarrow\frac{1+\left(x+11\right)}{115}+\frac{1+\left(x+22\right)}{104}=\frac{1+\left(x+33\right)}{93}+\frac{1+\left(x+44\right)}{82}\)
\(\Leftrightarrow\frac{x+126}{115}+\frac{x+126}{104}=\frac{x+126}{93}+\frac{x+126}{82}\)
\(\Leftrightarrow\left(x+126\right).\left(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\right)=0\)
\(\Leftrightarrow x+126=6\Leftrightarrow x=-126\)vì\(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\ne0\)
vậy x=-126
<=> 17.6x+90(x-19)+17.5(x+69)=0
<=> 102x+90x-1710+85x+5865=0
<=> 277x=-4155 => x=-4155/277=-15
ĐS: x=-15
Lí do = 0 nè:
\(\frac{x-39}{19}+\frac{x-49}{29}=\frac{x-5}{39}+\frac{x-69}{49}\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}=0+\left(\frac{x-5}{39}+\frac{x-69}{49}\right)\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\left(\frac{x-5}{39}+\frac{x-69}{49}\right)=0\)
=> \(\frac{x-39}{19}+\frac{x-49}{29}-\frac{x-5}{39}-\frac{x-69}{49}=0\)
\(x\)=\(\frac{69.125}{115}\)=\(75\)
\(\frac{x}{125}=\frac{69}{115}\)
\(\frac{x}{125}=\frac{3}{5}\)
\(\frac{x}{125}=\frac{75}{125}\)
\(\Rightarrow x=75\)