a/|x-1|=3=12
b/13+15+...+57+59
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Câu 1:
a) Ư(-12)={1;-1;2;-2;3;-3;4;-4;6;-6;12;-12}
b) B(-4)={0;-4;-8;4;8;...}
Câu 2:
a) Ta có: \(x-15=11-\left(-32\right)\)
\(\Leftrightarrow x-15=11+32\)
\(\Leftrightarrow x=43+15=58\)
Vậy: x=58
b) Ta có: \(13-\left(5-x\right)=7\)
\(\Leftrightarrow13-5+x=7\)
\(\Leftrightarrow x+8=7\)
hay x=-1
Vậy: x=-1
c) Ta có: \(x-\dfrac{3}{5}=5.12\)
\(\Leftrightarrow x-0.6=5.12\)
hay x=5,72
Vậy: x=5,72
d) Ta có: \(\dfrac{x+1}{-2}=\dfrac{-8}{x+1}\)
\(\Leftrightarrow\left(x+1\right)^2=\left(-2\right)\cdot\left(-8\right)=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-5\right\}\)
a) 13.7 + 7.7
= (13 + 7).7
= 20 . 7
= 140
b) 23 . 2016 . 52
= 8 . 2016 . 25
= 200 . 2016
= 403200
c) 32 . 15 - 5.9
= 9.15 - 5.9
= (15 - 5).9
= 10.9
= 90
d) 13 + 15 + ........... + 57 + 59
Áp dụng công thức tính dãy số ta có :
\(\frac{\left[\left(59-13\right):2+1\right].\left(59+13\right)}{2}=\frac{24.72}{2}=864\)
a) 13 . 7 + 7 . 7
= (13 + 7) . 7
= 20 . 7
= 140
b) 23 . 2016 . 52
= 8 . 2016 . 25
= ( 8 . 25 ) . 2016
= 200 . 2016
= 403200
c) 32 . 15 - 5 . 9
= 9 . 15 - 45
= 9 . 15 - 15 . 3
= ( 9 - 3 ) . 15
= 6 . 15
= 90
d) 13 + 15 + ........ + 57 + 59
Dãy số trên có số số hạng là:
( 59 - 13 ) : 2 + 1= 24 ( số hạng )
Tổng của dãy số trên là:
( 59 + 13 ) x 24 : 2 = 864
a) x+7=-12
x=(-12)-7
x=-19
b)x-15=-21
x=(-21)+15
x=-6
c)13-x=20
x=13-20
x=-7
d)17-(2+x)=3
x=17-3
x=14
x=14-2
x=12
a) tự làm
b) (57-17)+(58-18)+(59-19)+(60-20)+(61-21)=40+40+40+40+40=200
c) (9+15)+(11+13)+(-10-14)+(-12-12-4)=24+24-24-24-4=-4
d)-(1+2+3+.....+2007)=\(-\dfrac{\left(1+2007\right).2007}{2}=-2015028\)
a) (371-271)+(731-531)=100+200=300
b) (57-17)+(58-18)+(59-19)+(60-20)+(61-21)=40+40+40+40+40=200
c) (9+15)+(11+13)+(-10-14)+(-12-12-4)=24+24-24-24-4=-4
d)-(1+2+3+.....+2007)=−(1+2007).20072=−2015028
a) Ta có: \(7-\left(2x+4\right)=-\left(x+4\right)\)
\(\Leftrightarrow7-2x-4=-x-4\)
\(\Leftrightarrow-2x+3+x+4=0\)
\(\Leftrightarrow-x+7=0\)
\(\Leftrightarrow-x=-7\)
hay x=7
Vậy: S={7}
b) Ta có: \(\dfrac{2+x}{5}-0.5x=\dfrac{1-2x}{4}+0.25\)
\(\Leftrightarrow\dfrac{4\left(2+x\right)}{20}-\dfrac{0.5x\cdot20}{20}=\dfrac{5\left(1-2x\right)}{20}+\dfrac{20\cdot0.25}{20}\)
\(\Leftrightarrow4\left(2+x\right)-10x=5\left(1-2x\right)+5\)
\(\Leftrightarrow8+4x-10x=5-10x+5\)
\(\Leftrightarrow-6x+8=-10x+10\)
\(\Leftrightarrow-6x+8+10x-10=0\)
\(\Leftrightarrow4x-2=0\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)
d) Ta có: \(\dfrac{x-1}{59}+\dfrac{x-2}{58}+\dfrac{x-3}{57}=\dfrac{x-59}{1}+\dfrac{x-58}{2}+\dfrac{x-57}{3}\)
\(\Leftrightarrow\dfrac{x-1}{59}-1+\dfrac{x-2}{58}-1+\dfrac{x-3}{57}-1=\dfrac{x-59}{1}-1+\dfrac{x-58}{2}-1+\dfrac{x-57}{3}-1\)
\(\Leftrightarrow\dfrac{x-60}{59}+\dfrac{x-60}{58}+\dfrac{x-60}{57}=\dfrac{x-60}{1}+\dfrac{x-60}{2}+\dfrac{x-60}{3}\)
\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}\right)-\left(x-60\right)\left(1+\dfrac{1}{2}+\dfrac{1}{3}\right)=0\)
\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)
mà \(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\ne0\)
nên x-60=0
hay x=60
Vậy: S={60}
1.73.(8-59)-59.(8-73)
=73.8-73.59-59.8-59.73
=73.(59-59)-8.(73-59)
=73.0-8.14
=0-112
=-112
2.159.(18-59)-59.(18 - 159)
=159.18-59.159-59.18-59.159
=159.(59-59)-18.(159-59)
=159.0-18.100
=0-1800
=-1800
\(1b,\)\(Số\)số hạng là (59-13):2=23
Tổng là (59+13).23 :2=828
Nhó tích