A: 121212/131313 + 154154/143143- (2121/2323 + 275275/253253)
tính bằng cách thuận tiện nhất .mọi người cố gắng giúp mình nha
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\(A=\frac{12\cdot10101}{13\cdot10101}+\frac{14\cdot11011}{13\cdot11011}-\left(\frac{21\cdot101}{23\cdot101}+\frac{25\cdot11011}{23\cdot11011}\right)\)
\(A=\frac{12}{13}+\frac{14}{13}-\left(\frac{21}{23}+\frac{25}{23}\right)\)
\(A=0\)
nhớ cho đúng nha
\(A=\frac{121212}{131313}+\frac{154154}{143143}-\left(\frac{2121}{2323}+\frac{275275}{253253}\right)\)
\(\Leftrightarrow A=\frac{12}{13}-\frac{14}{13}-\left(\frac{21}{23}+\frac{25}{23}\right)\) (Áp dụng phương pháp rút gọn phân số)
\(\Leftrightarrow A=\frac{12}{13}-\frac{14}{13}-\frac{46}{23}=\frac{\left(-2\right)}{13}-\frac{46}{23}\)
\(\Leftrightarrow A=-\frac{28}{13}\)
7.15 : 0.5 + 7.15 x 9 - 7.15
= 14.3 + 7.15 x ( 9 - 1 )
= 14.3 + 7.15 x 8
= 14.3 + 57.2
= 71.5
\(\frac{12x101x13x10101}{13x101x12x10101}=\frac{12x10101x13x101}{12x10101x13x101}=\frac{121212x1313}{121212x1313}=1.\)
12,12 x 7,5 + 12,12 : 2 + 12,12 + 12,12
= 12,12 x 7,5 + 12,12 x 0,5 + 12,12 x 1 + 12,12 x 1
= 12,12 x (7,5 + 0,5 + 1 + 1)
= 12,12 x 10
= 121,2
999 x 4,26 - 333 x 2,78
= 333 x 2 x 4,26 - 333 x 2,78
= 333 x ( 2 x 4,26 - 2,78 )
= 333 x 5,74
= 1911,42
999x4,26-333x2,78
=333x3x4,26-333x2,78
=333x12,78-333x2,78
=333x(12,78-2,78)
=333x10
=3330
\(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)
\(=\dfrac{21}{23}+\dfrac{125}{143}+\left(\dfrac{-21}{23}\right)+\left(\dfrac{-125}{143}\right)\)
\(=\dfrac{21}{23}+\dfrac{125}{143}-\dfrac{21}{23}-\dfrac{125}{143}\)
\(=0\)
\(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)
\(=\dfrac{21}{23}+\dfrac{125}{93}+\dfrac{-21}{23}+\dfrac{-125}{143}\)
\(=125\left(\dfrac{1}{93}-\dfrac{1}{143}\right)\)
\(=\dfrac{6250}{13299}\)
\(\dfrac{121212}{242424}+\dfrac{1313}{2626}+\dfrac{20212021}{40424042}\)
= \(\dfrac{12}{24}+\dfrac{13}{26}+\dfrac{2021}{4042}\)
= \(\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}\)
= \(\dfrac{3}{2}\)
121212/242424+1313/2626+20212021/404244024
= 1/2+1/2+1/2
=3/2
\(A=\dfrac{121212}{131313}+\dfrac{154154}{143143}-\left(\dfrac{2121}{2323}+\dfrac{275275}{253253}\right)\)
\(=\dfrac{12}{13}+\dfrac{14}{13}-\left(\dfrac{21}{23}+\dfrac{25}{23}\right)\)
\(=2-2=0\)