20 - [ 7 ( x - 3 ) + 4 ] =2
Các bn giúp mik nha!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(x-\dfrac{1}{2}\right).\dfrac{5}{2}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right).\dfrac{5}{2}=\dfrac{5}{4}\)
\(\Rightarrow x-\dfrac{1}{2}=\dfrac{1}{2}\)
=> x = 1
Ta có: \(\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{2}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{2}=\dfrac{5}{4}\)
\(\Leftrightarrow x-\dfrac{1}{2}=\dfrac{1}{2}\)
hay x=1
\(\dfrac{x+2}{-4}=-\dfrac{9}{x+2}\\ \Rightarrow\left(x+2\right)^2=\left(-4\right).\left(-9\right)\\ \Rightarrow\left(x+2\right)^2=36\\ \Rightarrow\left(x+2\right)^2=\pm6^2\\ \Rightarrow\left[{}\begin{matrix}x+2=6\\x+2=-6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=4\\x=-8\end{matrix}\right.\)
-3(x+4)(x-7)+7(x-5)(x-1)
=\(-3\left(x^2-3x-28\right)+7\left(x^2-6x+5\right)\)
= \(-3x^2+9x+84+7x^2-42x+35\)
= \(4x^2-33x+119\)
7(x - 3) - x(3 - x)
= (x - 3)(7 + x)
chỉ bt có v mà k bt có đúng k
1 ) 7 ( x - 3 ) - x ( 3 - x )
= 7 ( x - 3 ) + x ( x - 3 )
= ( x - 3 ) ( 7 + x )
2 ) 4x2 - 6x + 3 - 2x
= 4x2 - 2x - 6x + 3
= 2x ( 2x - 1 ) - 3 ( 2x - 1 )
= ( 2x - 1 ) ( 2x - 3 )
3 ) ( 4 - x ) - 4x + x2
= ( 4 - x ) - x ( 4 - x )
= ( 4 - x ) ( 1 - x )
4 ) x2 - 2xy + y2
= ( x - y )2
A\(\frac{7}{8}+\frac{7}{12}+\frac{9}{8}+\frac{5}{12}\)
\(=\left(\frac{7}{12}+\frac{5}{12}\right)+\left(\frac{7}{8}+\frac{9}{8}\right)\)
\(=1+2\)
\(=3\)
\(5\frac{8}{7}\div x-\frac{4}{17}\div x+3\frac{1}{7}\div17\frac{1}{3}=\frac{4}{11}\)
\(\Leftrightarrow\frac{43}{7}\div x-\frac{4}{17}\div x+\frac{22}{7}\div\frac{52}{3}=\frac{4}{11}\)
\(\Leftrightarrow\left(\frac{43}{7}-\frac{4}{17}\right)\div x+\frac{33}{182}=\frac{4}{11}\)
\(\Leftrightarrow\frac{703}{119}\div x+\frac{33}{182}=\frac{4}{11}\)
\(\Leftrightarrow\frac{703}{119}\div x=\frac{365}{2002}\)
\(\Leftrightarrow x=32,40257857\)( Casio nó k hiện phân số nên mình viết tạm vầy nhé :)
a)\(x\left(x-3\right)-2x+6=0\)
\(\Leftrightarrow x\left(x-3\right)-2\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=3\end{cases}}\)
b)\(\left(3x-5\right)\left(5x-7\right)+\left(5x+1\right)\left(2-3x\right)=4\)
\(\Leftrightarrow15x^2-46x+35-15x^2+7x+2-4=0\)
\(\Leftrightarrow33-39x=0\Leftrightarrow33=39x\Leftrightarrow x=\frac{33}{39}\)
a) \(x\left(x-3\right)-2x+6=0\)
\(x\left(x-3\right)-2\left(x-3\right)=0\)
\(\left(x-3\right)\left(x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x-2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=2\end{cases}}}\)
b) \((3x-5)(5x-7)+(5x+1)(2-3x)=4\)
\(15x^2-46x+35+10x-15x^2+2-3x-4=0\)
\(33-39x=0\)
\(3\left(11-13x\right)=0\)
\(11-13x=0\)
\(13x=11\)
\(x=\frac{11}{13}\)