Tính hợp lý:
73.9+73.74-45.539
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a) 23.125+78.125-125
= (23+78-1).125
= 100.125
= 12500
b) 37.46+18.54-17.46+54.2
= (37-17).46+(18+2).54
= 20.46+20.54
= 20.(46+54)
= 20.100
= 2000
c) 3.22-23:2+22
= 3.22-22+22
= 3.22
= 3.4
= 12
d) 73.9+32.74-45.539
= 73.9+9.74-5.9.72.11
= 9.(73+74)-5.9.72.11
=9.2744-9.2695
= 9.(2744-2695)
= 9.49
= 441
a/
=125(23+78-1)=125.100=12500
b/
=46(37-17)+54(18+2)
=20(46+54)=20.100=2000
c/
=3.22-22+22=3.4=12
d/
=73.32+32.74-5.32.72.11=
=32.72(7+72-55)=32.72=441
\(a,23\cdot125+78\cdot125-125\\ =125\cdot\left(23+78-1\right)\\ =125\cdot100\\ =12500\\ b,37\cdot46+18\cdot54-17\cdot46+54\cdot2\\ =46\cdot\left(37-17\right)+54\cdot\left(18+2\right)\\ =46\cdot20+54\cdot20\\ =20\cdot\left(46+54\right)\\ =20\cdot100\\ =2000\\ b,3\cdot2^2-2^3:2+2^2\\ =3\cdot4-4+4\\ =12\\ d,7^3\cdot9+3^2\cdot7^4\\ =7^3\cdot9+7^4\cdot9\\ =7^3\cdot9\cdot\left(1+7\right)\\ =343\cdot9\cdot8\\ =24696\)
a) \(23\cdot125+78\cdot125-125\)
\(=125\cdot\left(23+78-1\right)\)
\(=125\cdot100\)
\(=12500\)
b) \(37\cdot46+18\cdot54-17\cdot46+54\cdot2\)
\(=54\cdot\left(18+2\right)+46\cdot\left(37-17\right)\)
\(=54\cdot20+46\cdot20\)
\(=54\cdot\left(20+46\right)\)
\(=20\cdot100\)
\(=2000\)
c) \(3\cdot2^2-2^3:2+2^2\)
\(=3\cdot2^2-2^2+2^2\)
\(=3\cdot2^2\)
\(=3\cdot4\)
\(=12\)
d) \(7^3\cdot9+3^2\cdot7^4\)
\(=7^3\cdot3^2+3^2\cdot7^4\)
\(=7^3\cdot3^2\cdot\left(1+7\right)\)
\(=24696\)
1/1.2 + 1/2.3 + 1/3.4 + ... + 1/73.74 + 1/74.75
= 1-1/2+1/2-1/3+1/3-1/4+...+1/73-1/74+1/74-1/75
= 1 - 1/75
= 74/75
Nhấn đúng cho mk nha!!!!!!!!!!!
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{73.74}+\frac{1}{74.75}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{73}-\frac{1}{74}+\frac{1}{74}-\frac{1}{75}\)
\(=1-\frac{1}{75}\)
\(=\frac{74}{75}\)
b) 73.9+ 32.74- 45.539
=343.9+9.2401-45.539
=9.(343+2401)-45.539
=9.2744-24355
=24696-24355
=341
a) 132- (116-(132-1282))
=132- ( 116-(132-16384))
=132-(116+16252)
=132-16368
=16236
=(-259+259)+[(-74)+(-26)]+(-81+581)
=0+(-100)+500
=400
= -259 + 259 - 74 - 26 + 581 + 259 - 81
= 0 - 100 + 840 - 81
= 659
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{8}{9}-\frac{51}{13}.\frac{1}{3}\)
\(=\frac{7}{5}-\left(\frac{32}{60}+\frac{15}{60}\right).\frac{8}{9}-\frac{17}{13}\)
\(=\frac{7}{5}-\frac{47}{60}.\frac{8}{9}-\frac{17}{13}\)
\(=\frac{7}{5}-\frac{94}{135}-\frac{17}{13}\)
\(=\frac{-212}{351}\)
Tự quy đồng
\(2\frac{3}{4}.\left(-0,4\right)-1\frac{3}{5}.2,75+\left(-1,2\right):\frac{4}{11}\)
\(=\frac{11}{4}.\frac{-2}{5}-\frac{8}{5}.\frac{11}{4}-\frac{6}{5}.\frac{11}{4}\)
\(=\frac{11}{4}.\left(\frac{-2}{5}-\frac{8}{5}-\frac{6}{5}\right)\)
\(=\frac{11}{4}.\frac{-16}{5}\)
\(=\frac{-44}{5}=-8\frac{4}{5}\)
\(=2.6\cdot\left(-2\right):2=2.6\cdot\left(-1\right)=-2.6\)
7^3 . 9 + 7^3 . 7^4 - 45 . 539
= 343 .9 + 343 . 2401 - 45 . 539
= 343 . (9 + 2401) - 45 . 539
= 343 . 2410 - 24255
= 826630 - 24255
= 802375
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