a, 12.19+12.34+12.20+88.27
b, 28.17+66.14
c, 423134.846267-423133/846267.423133+423134
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13 tháng 8 2016
a)\(2.18.6+3.19.4+12.63\)
\(=2.6.18+3.4.19+12.63\)
\(=12.18+12.19+12.63\)
\(=12.\left(18+19+63\right)\)
\(=12.100\)
\(=1200\)
b)\(12.19+12.34+12.20+88.27\)
\(=12.19+12.34+12.20+22.4.3.9\)
\(=12.19+12.34+12.20+4.3.22.9\)
\(=12.19+12.34+12.20+12.198\)
\(=12.\left(19+34+20+198\right)\)
\(=12.271\)
\(=3252\)
c) \(28.17+66.14\)
\(=14.2.17+66.14\)
\(=14.34+66.14\)
\(=14.\left(34+66\right)\)
\(=14.100\)
\(=1400\)
NY
13 tháng 8 2016
a,2.18.6=216; 3.19.4=228;12.63= 756;216+228+756=1200 b,12.19=228;12.34=408;12.20=240;88.27=2376;228+408+240+2376=3252 c,1/1
NP
1
IE
3
10 tháng 7 2015
\(\frac{423134.846267-423133}{846267.423133+423134}\)
Xét tử số : 423134.846267-423133
= (423133+1).846267-423133
= 423133.846267+846267-423133
=423133.846267+ 423134
Ta có : \(\frac{423133.846267+423134}{846267.423133+423134}\)=1
XN
0
VT
1
NN
11 tháng 1 2018
\(\dfrac{423134.846267-423133}{846267.423133+423134}.\)
\(=\dfrac{\left(423133+1\right).846267-423133}{846267.423133+423134}.\)
\(=\dfrac{423133.846267+\left(846267-423133\right)}{846267.423133+423134}.\)
\(=\dfrac{423133.846267+423134}{846267.423133+423134}=1.\)
Vậy..........
NT
3
4 tháng 8 2016
\(\frac{423134.846267-423133}{846267.423133+423134}=\frac{\left(423134+1\right).846267-423133}{846267.423133+423134}\)
\(\frac{423133.846267+846267-423133}{846267.423133-423134}=\frac{423133.846267-423134}{864267.423133-423134}=1\)
NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
11 tháng 10 2018
\(=\frac{\left(423133+1\right).846267-423133}{846267.423133+423134}=\frac{846267.423133+846267-423133}{846267.423133+423134}=\)
\(=\frac{846267.423133+423134}{846267.423133+423134}=1\)
VT
1
11 tháng 1 2018
\(\dfrac{423134\cdot846267-423133}{846267\cdot423133+423134}\)
\(=\dfrac{(423133+1)\cdot846267-423133}{846267\cdot423133+423134}\)
\(=\dfrac{423133\cdot846267+846267-423133}{846267\cdot423133+423134}\)
\(=\dfrac{423133\cdot846267+423134}{864267\cdot423133+423134}=1\)
=125
=94,31
125
94,31