1\(\dfrac{13}{15}\) \(\times\) 0,75 (\(\dfrac{8}{15}\) \(+\) 0,25 )\(\times\) \(\dfrac{24}{47}\)
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\(1\dfrac{13}{15}.0,75-\left(\dfrac{8}{15}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{8}{15}+\dfrac{1}{4}\right).\dfrac{24}{47}-\dfrac{51}{13}:3\)
\(=\dfrac{7}{5}-\dfrac{47}{60}.\dfrac{24}{47}-\dfrac{17}{13}\)
\(=\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)
\(=1-\dfrac{17}{13}=-\dfrac{4}{13}\)
=28/15*3/4-(104/195+1/4)*24/47-(1+4/13)
=7/5-2/5-1-4/13
=-4/13
mink không chép lại đề nha bạn
\(\dfrac{28}{15}\).\(\dfrac{3}{4}\)\(-\)\(\left(\dfrac{104}{195}+\dfrac{1}{4}\right).\dfrac{24}{47}-\dfrac{51}{13}:3\)
\(\dfrac{7}{5}\)\(-\dfrac{23}{60}\).\(\dfrac{24}{47}\)\(-\dfrac{17}{13}\)
\(\dfrac{7}{5}\)\(-\dfrac{46}{235}\)\(-\dfrac{17}{13}\)
\(\dfrac{283}{235}\)\(-\dfrac{17}{13}\)
= (đến đây bạn tự tính ra kết quả nhé)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{8}{15}+\dfrac{1}{4}\right)\cdot\dfrac{24}{47}-\dfrac{51}{13}\cdot\dfrac{1}{3}\\ =\dfrac{7}{5}-\dfrac{47}{60}\cdot\dfrac{24}{47}-\dfrac{17}{13}\\ =\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)
\(=1-\dfrac{17}{13}=-\dfrac{4}{13}\)
a) \(0,2\cdot\dfrac{15}{36}-\left(\dfrac{2}{5}+\dfrac{2}{3}\right):1\dfrac{1}{5}\)
\(=\dfrac{1}{12}-\dfrac{16}{15}\cdot\dfrac{5}{6}\)
\(=\dfrac{1}{12}-\dfrac{8}{9}\)
\(=\dfrac{-29}{36}\)
b) \(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{8}{15}+0,25\right)\cdot\dfrac{24}{27}\)
\(=\dfrac{28}{15}\cdot0,75-\dfrac{47}{60}\cdot\dfrac{24}{27}\)
\(=\dfrac{7}{5}-\dfrac{94}{135}\)
\(=\dfrac{19}{27}\)
c) \(5:\left(4\dfrac{3}{4}-1\dfrac{25}{28}\right)-1\dfrac{3}{8}:\left(\dfrac{3}{8}+\dfrac{9}{20}\right)\)
\(=5\cdot\dfrac{7}{20}-\dfrac{11}{8}\cdot\dfrac{40}{33}\)
\(=\dfrac{7}{4}-\dfrac{5}{3}\)
\(=\dfrac{1}{12}\)
a) \(\dfrac{2}{4}\times\dfrac{9}{5}=\dfrac{1}{2}\times\dfrac{9}{5}=\dfrac{1\times9}{2\times5}=\dfrac{9}{10}\)
b) \(\dfrac{13}{8}\times\dfrac{5}{15}=\dfrac{13}{8}\times\dfrac{1}{3}=\dfrac{13}{24}\)
c) \(\dfrac{3}{9}\times\dfrac{6}{12}=\dfrac{1}{3}\times\dfrac{1}{2}=\dfrac{1}{3\times2}=\dfrac{1}{6}\)
a: =18/20=9/10
b: \(=\dfrac{13\cdot5}{8\cdot15}=\dfrac{13}{8}\cdot\dfrac{1}{3}=\dfrac{13}{24}\)
c: \(=\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{6}\)
1\(\dfrac{13}{15}.0,75-\left(\dfrac{104}{195}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)
=\(\dfrac{28}{15}.\dfrac{3}{4}-\dfrac{47}{60}.\dfrac{24}{47}-\dfrac{51}{13}.\dfrac{1}{3}\)
=\(\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)
=\(1-\dfrac{17}{13}\)
=\(-\dfrac{4}{13}\)
5 x ( \(\dfrac{-5}{2}\) )2 + \(\dfrac{2}{15}\) x \(\sqrt{\dfrac{9}{4}}\) - ( -2022)0 + | -0,25|
= 5 x \(\dfrac{25}{4}\) + \(\dfrac{2}{15}\) x \(\dfrac{3}{2}\) - 1 + 0,25
= \(\dfrac{125}{4}\) + \(\dfrac{1}{5}\) - ( 1 - 0,25)
= 31,25 + 0,2 - 0,75
= 31,45 - 0,75
= 30,7
\(1\dfrac{13}{15}\cdot0,75\cdot\left(\dfrac{8}{15}+0.25\right)\cdot\dfrac{24}{47}\)
= \(\dfrac{28}{15}\cdot\dfrac{3}{4}\cdot\left(\dfrac{8}{15}+\dfrac{1}{4}\right)\cdot\dfrac{24}{47}\)
= \(\dfrac{7}{5}\cdot\dfrac{47}{60}\cdot\dfrac{24}{47}\)
\(=\dfrac{329}{300}\cdot\dfrac{24}{47}\)
\(=\dfrac{14}{25}\)
14/25