\(\frac{254x399-145}{254+399x253}\)
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(253+1)x399-145/254+399x253
=253x399+(399-145)/254+399x253
=253x399+254/254+399x253
=1
Ta có:
\(\frac{254X399-145}{254+399X253}\)
\(=\frac{\left(253+1\right)X399-154}{254+399X253}\)
\(=\frac{253X399+399-154}{254+399X253}\)
\(=\frac{253X399+254}{253X399+254}\)
\(=1\)
254 x 399 - 145/254 + 339 x 253
= 101346 - 145/254 + 85767
= 187112,4291
\(\frac{254\cdot399-145}{254+399\cdot253}=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+254}{254+399\cdot253}\)
\(=1\)
A = \(\dfrac{254\times399-145}{254+399\times253}\)
A = \(\dfrac{\left(253+1\right)\times399-145}{254+399\times253}\)
A = \(\dfrac{253\times399+399-145}{254+399\times253}\)
A = \(\dfrac{253\times399+254}{254+399\times253}\)
A = 1
a) \(254x399-145=\left(250+4\right)\left(400-1\right)-145\)
\(=100000+1600-250-145-4=101600-\left(250+145+4\right)\)
\(=101600-399=101201\)
b) \(254+399x253=254+\left(400-1\right)x\left(250+3\right)\)
\(=254+100000+1200-250-3\)
\(=101454-250-3=101201\)
a, \(\dfrac{254\times399-145}{254+399\times253}\)
= \(\dfrac{\left(253+1\right)\times399-`45}{254+399\times253}\)
= \(\dfrac{253\times399+399-145}{253\times399+254}\)
= \(\dfrac{253\times399+254}{253\times399+254}\)
= 1
b, \(\dfrac{5932+6001\times5931}{5932\times6001-69}\)
= \(\dfrac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)
= \(\dfrac{5932+6001\times5931}{5931\times6001+6001-69}\)
= \(\dfrac{5932+6001\times5931}{5931\times6001+5932}\)
= 1
254 × 399 - 145 / 254 + 399 × 253
= (253 + 1) × 399 - 145 / 254 + 399 × 253
= 253 × 399 + (399 - 145) / 254 + 399 × 253
= 253 × 399 + 254 / 254 + 399 × 253
= 1
\(\frac{254x399-145}{254+399x253}\)
\(=\frac{253x399+399-145}{254+399x253}\)
\(=\frac{253x399+254}{254+399x253}=1\)
\(\frac{254+399.253}{254.399-145}=\frac{254+399.253}{\left(253+1\right).399-145}=\frac{254+399.253}{253.399+\left(399-145\right)}\)
\(=\frac{399.253+254}{399.353+354}=1\)
\(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}=\frac{253.399+\left(399-145\right)}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}=1\)
\(\frac{254\times399-145}{254+399\times253}\)
\(=\frac{253\times399+399-145}{254+399\times253}\)
\(=\frac{253\times399+254}{254+399\times253}\)
\(=1\)