4.{\(^{3^2}\).[(\(^{5^2}\)+\(^{2^3}\)):11]-26}+2009=...
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\(4.\left\{3^2.\left[\left(5^2+2^3\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[\left(25^{ }+8\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[33:11\right]-26\right\}+2009\)
\(=4.\left\{9.3-26\right\}+2009\) \(=4.\left(27-26\right)+2009\)
\(=4.1+2009=2013\)
1.
Xét tổng $2+4+6+....+2014$:
Số số hạng: $(2014-2):2+1=1007$
Giá trị tổng trên là: $(2014+2).1007:2=1010021$
Xét tổng $3+5+...+2011$:
Số số hạng: $(2011-3):2+1=1005$
Giá trị tổng trên: $(2011+3).1005:2=1012035$
$A=1010021-1012035=-2014$
\(\dfrac{3}{5}+\dfrac{-4}{3}=\dfrac{9}{15}+\dfrac{-20}{15}=\dfrac{-11}{15}\)
\(2+\dfrac{-5}{4}=\dfrac{8}{4}+\dfrac{-5}{4}=\dfrac{3}{4}\)
\(\dfrac{-2}{13}+\dfrac{-11}{26}=\dfrac{-4}{26}+\dfrac{-11}{26}=\dfrac{-15}{26}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\dfrac{3}{4}+\dfrac{2}{3}+\dfrac{3}{5}\)
`=`\(\dfrac{9}{12}+\dfrac{8}{12}+\dfrac{3}{5}\)
`=`\(\dfrac{17}{12}+\dfrac{3}{5}\)
`=`\(\dfrac{85}{60}+\dfrac{36}{60}\)
`=`\(\dfrac{121}{60}\)
`b)`
\(\dfrac{1}{2}\cdot\dfrac{9}{13}\div\dfrac{27}{26}\)
`=`\(\dfrac{1}{2}\cdot\dfrac{9}{13}\cdot\dfrac{26}{27}\)
`=`\(\dfrac{1}{2}\cdot\dfrac{2}{3}\)
`=`\(\dfrac{1}{3}\)
`c)`
\(\dfrac{2}{7}\cdot\dfrac{1}{9}+\dfrac{2}{7}\cdot\dfrac{2}{9}+\dfrac{1}{3}\cdot\dfrac{5}{7}\)
`=`\(\dfrac{2}{7}\cdot\left(\dfrac{1}{9}+\dfrac{2}{9}\right)+\dfrac{1}{3}\cdot\dfrac{5}{7}\)
`=`\(\dfrac{2}{7}\cdot\dfrac{1}{3}+\dfrac{1}{3}\cdot\dfrac{5}{7}\)
`=`\(\dfrac{1}{3}\cdot\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\)
`=`\(\dfrac{1}{3}\cdot1=\dfrac{1}{3}\)
`d)`
\(11\div\dfrac{5}{2}+11\div\dfrac{7}{3}+11\div\dfrac{35}{6}\)
`=`\(11\cdot\dfrac{2}{5}+11\cdot\dfrac{3}{7}+11\cdot\dfrac{6}{35}\)
`=`\(11\cdot\left(\dfrac{2}{5}+\dfrac{3}{7}+\dfrac{6}{35}\right)\)
`=`\(11\cdot1=11\)
a) 3/4 + 2/3 + 3/5 = 45/60 + 40/60 + 36/60 = 121/60
b) 1/2 x 9/13 : 27/26 = 9/26 x 26/27 = 1/3
c) 2/7 x 1/9 + 2/7 x 2/9 + 1/3 x 5/7 = 2/7 x (1/9 + 2/9) + 5/21 = 2/7 x 1/3 + 5/21 = 2/21 + 5/21 = 1/3
d) 11 : 5/2 + 11 : 7:3 + 11 : 35/6 = 11 x (2/5 + 3/7 + 6/35) = 11 x 1 = 11
Số số hạng của dãy:(2010-7):1+1=2004(số)
Vậy có tất cả:2004:2=1002(cặp)
A=7-8+9-10+11-12+...+2009-2010
A=(7-8)+(9-10)+(11-12)+...+(2009-2010)
A=-1+(-1)+(-1)+...+(-1)
Vậy A=(-1)*1002=-1002
Linh tự mở ngoac giup tớ nhe
4.(9.((25+8):11)-26)+2009
=4.(9.(33:11)-26)+2009
=4.(9.3-26)+2009
=4.1+2009
=2013
\(4.\left\{3^2.\left[\left(5^2+2^3\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[\left(25+8\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[33:11\right]-26\right\}+2009\)
\(=4.\left\{9.3-26\right\}+2009\)
\(=4.\left\{27-26\right\}+2009\)
\(=4.1+2009\)
\(=4+2009=2013\)