x3+x2Y+xy3+y3
8+4+6+7 với x=-8;y=6
.
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)=\(3x^3-15x^2+21x\)
b)\(=-2x^4y-10x^2y+2xy\)
c)\(=-x^3+6x^2+5x-4x^2+24x+20=-x^3+2x^2+29x+20\)
d)\(=2x^4-3x^3+4x^2-2x^2+3x-4=2x^4-3x^32x^2+3x-4\)
e)\(=x^2-4y^2\)
f)\(=-2x^2y^3+y-3\)
g)\(=3xy^4-\dfrac{1}{2}y^2+2x^2y\)
h)\(=9x^2-6x+1-7x^2-14=2x^2-6x-13\)
i)\(=x^2-x-3\)
j)\(=\left(x+2y\right)\left(x^2-2y+4y^2\right):\left(x+2y\right)=x^2-2y+4y^2\)
a: \(=\dfrac{35x^3-14x^2+55x^2-22x+35x-14+9}{5x-2}\)
\(=7x^2-11x+7+\dfrac{9}{5x-2}\)
b: \(=\dfrac{\left(2x-3\right)\left(4x^2+6x+9\right)}{2x-3}=4x^2+6x+9\)
a)\(\left(x-y\right)\left(x^3+x^2y+xy^2+y^3\right)=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4=x^4-y^4\)
b) \(x\left(3x-18\right)-3\left(x-4\right)\left(x-2\right)+8=3x^2-18x-3x^2+18x-24+8=-16\)
a)
=(x-2)3
b)\(\left(2-x\right)^3\)
c)\(\left(x+\dfrac{1}{3}\right)^3\)
d)\(\left(\dfrac{x}{2}+y\right)^3\)
e)
\(=\left(x-1\right)^2\left(x-1-15\right)+25\left[3\left(x-1\right)-5\right]\)
\(=\left(x-1\right)^2\left(x-16\right)+25\left(3x-3-5\right)\)
\(=\left(x-1\right)^2\left(x-16\right)+25\left(3x-8\right)\)
a/ \(P+Q=\left(x^2y+x^3-xy^2+3\right)+\left(x^3+xy^2-xy-6\right)\)
\(=x^2y+x^3-xy^2+3+x^3+xy^2-xy-6\)
\(=\left(x^3+x^3\right)+\left(xy^2-xy^2\right)+\left(3-6\right)+x^2y-xy\)
\(=2x^3+x^2y-xy-3\)
b/ \(M+N=\left(x^2y+0,5xy^3-7,5x^3y^2+x^3\right)+\)
\(\left(3xy^3-x^2y+5,5x^3y^2\right)\)
\(=x^2y+0,5xy^3-7,5x^3y^2+x^3+3xy^3-x^2y+5,5x^3y^2\)
\(=\left(x^2y-x^2y\right)+\left(0,5xy^3+3xy^3\right)+\left(5,5x^3y^2-7,5x^3y^2\right)+x^3\)
\(=3,5xy^3-2x^3y^2+x^3\)
a) \(4x^2-16+\left(3x+12\right)\left(4-2x\right)\)
\(=\left(2x-4\right)\left(2x+4\right)-3\left(x+4\right)\left(2x-4\right)\)
\(=\left(2x-4\right)\left(2x+4-3x-12\right)\)
\(=-\left(2x-4\right)\left(x+8\right)\)
b) \(x^3+x^2y-15x-15y\)
\(=x^2\left(x+y\right)-15\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2-15\right)\)
c) \(3\left(x+8\right)-x^2-8x\)
\(=3\left(x+8\right)-x\left(x+8\right)\)
\(=\left(x+8\right)\left(3-x\right)\)
d) \(x^3-3x^2+1-3x\)
\(=x^3+1-3x^2-3x\)
\(=\left(x+1\right)\left(x^2-x+1\right)-3x\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-x+1-3x\right)\)
\(=\left(x+1\right)\left(x^2-4x+1\right)\)
d) \(5x^2-5y^2-20x+20y\)
\(=5\left(x^2-y^2\right)-20\left(x-y\right)\)
\(=5\left(x-y\right)\left(x+y\right)-20\left(x-y\right)\)
\(=5\left(x-y\right)\left(x+y-4\right)\)
Ta có: \(\left(x^3-x^2y+xy^2-y^3\right)\left(x+y\right)\)
\(=\left[x^2\left(x-y\right)+y^2\left(x-y\right)\right]\left(x+y\right)\)
\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)
\(=x^4-y^4=2^4-\left(\dfrac{1}{2}\right)^4=16-\dfrac{1}{16}=\dfrac{255}{16}\)
Bài 2: cho B= xy3-x2y. tính giá trị của B khi : a, x=1,y=1; b, x=-1,y=-1; c,x=1, y=-1; d, x=-1; y=1.
a: \(B=xy\left(y^2-x\right)=1\cdot1\cdot\left(1^2-1\right)=0\)
b: \(B=xy\left(y^2-x\right)=-1\cdot\left(-1\right)\cdot\left[\left(-1\right)^2-\left(-1\right)\right]=1\cdot\left(1+1\right)=2\)
c: \(B=xy\left(y^2-x\right)=1\cdot\left(-1\right)\cdot\left[\left(-1\right)^2-1\right]=0\)
d: \(B=xy\left(y^2-x\right)=-1\cdot1\cdot\left[1^2-\left(-1\right)^2\right]=0\)
Bài 2:
\(B=xy^3-x^2y=xy\left(y^2-x\right)\)
a) \(x=1;y=1\Rightarrow B=1.1.\left(1^2-1\right)=0\)
b) \(x=-1;y=-1\Rightarrow B=\left(-1\right).\left(-1\right).\left[\left(-1\right)^2-\left(-1\right)\right]=2\)
c) \(x=1;y=-1\Rightarrow B=1.\left(-1\right).\left[\left(-1\right)^2-\left(-1\right)\right]=-2\)
d) \(x=-1;y=1\Rightarrow B=\left(-1\right).1.\left[1^2-\left(-1\right)\right]=-2\)
X2O3 => X hóa trị III
YH2 => Y hóa trị VI
=> CTHH giữa X và Y là : X2Y3
=> CHỌN A