Âm hai mũ mười lăm trên hai mũ mười hai =???
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10\(^2\)=100
10\(^3\)=1000
10\(^4\)=10000
10\(^5\)=100000
10\(^6\)=1000000
K nhé ????
Câu 1:
1; 125 : 52
= 53 : 52
= 51
2; 275 : 813
= (33)5 : (34)3
= 315 : 312
= 33
3; 84.165.32
= (23)4.(24)5.25
= 212.220.25
= 237
Câu 1
4; 274.8110
= (33)4.(34)10
= 312.340
= 352
ốn cộng hai mũ bai cộng hai mũ ba cộng hai mũ bốn cộng.........hai mũ mười chín cộng hai mũ hai mươi
Đặt A = 4 + 22 + 23 + 24 + ... + 29 + 210
= 4 + ( 22 + 23 + 24 + ... + 29 + 210 )
Đặt B = 22 + 23 + 24 + ... + 29 + 210
=> 2B = 2( 22 + 23 + 24 + ... + 29 + 210 )
= 23 + 24 + ... + 210 + 211
=> B = 2B - B
= 23 + 24 + ... + 210 + 211 - ( 22 + 23 + 24 + ... + 29 + 210 )
= 23 + 24 + ... + 210 + 211 - 22 - 23 - 24 - ... - 29 - 210
= 211 - 22 = 211 - 4
=> B = 211 - 4
Thế B vào A ta được :
A = 4 + 211 - 4 = 211
Ta có -15/x = 12/20
suy ra 12.x = -15.20
12.x = -300
x = -300 : 12
x = -25
a) \(12\cdot\left(-\dfrac{2}{3}\right)^2+\dfrac{4}{3}\)
\(=12\cdot\dfrac{4}{9}+\dfrac{4}{3}\)
\(=\dfrac{12\cdot4}{9}+\dfrac{4}{3}\)
\(=\dfrac{16}{3}+\dfrac{4}{3}\)
\(=\dfrac{16+4}{3}\)
\(=\dfrac{20}{3}\)
b) \(\left(\dfrac{3}{2}\right)^2-\left[0,5:2-\sqrt{81}\cdot\left(-\dfrac{1}{2}\right)^2\right]\)
\(=\dfrac{9}{4}-\left(\dfrac{1}{2}:2-9\cdot\dfrac{1}{4}\right)\)
\(=\dfrac{9}{4}-\left(\dfrac{1}{4}-9\cdot\dfrac{1}{4}\right)\)
\(=\dfrac{9}{4}-\dfrac{1}{4}\cdot\left(1-9\right)\)
\(=\dfrac{9}{4}+\dfrac{8}{4}\)
\(=\dfrac{17}{4}\)
c) \(\left(-\dfrac{3}{4}+\dfrac{2}{3}\right):\dfrac{5}{11}+\left(-\dfrac{1}{4}+\dfrac{1}{3}\right)\)
\(=-\dfrac{1}{12}:\dfrac{5}{11}+\dfrac{1}{12}\)
\(=\dfrac{1}{12}\cdot-\dfrac{11}{5}+\dfrac{1}{12}\)
\(=\dfrac{1}{12}\cdot\left(-\dfrac{11}{5}+1\right)\)
\(=\dfrac{1}{12}\cdot-\dfrac{6}{5}\)
\(=-\dfrac{1}{10}\)
d) \(\dfrac{\left(-1\right)^3}{15}+\left(-\dfrac{2}{3}\right)^2:2\dfrac{2}{3}-\left|-\dfrac{5}{6}\right|\)
\(=-\dfrac{1}{15}+\dfrac{4}{9}:\left(2+\dfrac{2}{3}\right)-\dfrac{5}{6}\)
\(=-\dfrac{1}{15}+\dfrac{4}{9}:\dfrac{8}{3}-\dfrac{5}{6}\)
\(=-\dfrac{9}{10}+\dfrac{1}{6}\)
\(=-\dfrac{11}{15}\)
e) \(\dfrac{3^7\cdot8^6}{6^6\cdot\left(-2\right)^{12}}\)
\(=\dfrac{3^7\cdot\left(2^3\right)^6}{2^6\cdot3^6\cdot2^{12}}\)
\(=\dfrac{3^7\cdot2^{18}}{2^{6+12}\cdot3^6}\)
\(=\dfrac{2^{18}\cdot3^7}{2^{18}\cdot3^6}\)
\(=3^{7-6}\)
\(=3\)
\(a,12\cdot\left(-\dfrac{2}{3}\right)^2+\dfrac{4}{3}\\ =12\cdot\dfrac{4}{9}+\dfrac{4}{3}\\ =\dfrac{16}{3}+\dfrac{4}{3}\\ =\dfrac{20}{3}\\ b,\left(\dfrac{3}{2}\right)^2-\left[0,5:2-\sqrt{81}.\left(-\dfrac{1}{2}\right)^2\right]\\ =\dfrac{9}{4}-\left(\dfrac{1}{2}\cdot\dfrac{1}{2}-9\cdot\dfrac{1}{4}\right)\\ =\dfrac{9}{4}-\left(\dfrac{1}{4}-\dfrac{9}{4}\right)\\ =\dfrac{9}{4}-\left(-\dfrac{8}{4}\right)\\ =\dfrac{17}{4}\)
\(c,\left(-\dfrac{3}{4}+\dfrac{2}{3}\right):\dfrac{5}{11}+\left(-\dfrac{1}{4}+\dfrac{1}{3}\right)\\ =\left(-\dfrac{9}{12}+\dfrac{8}{12}\right)\cdot\dfrac{11}{5}+\left(-\dfrac{3}{12}+\dfrac{4}{12}\right)\\ =-\dfrac{1}{12}\cdot\dfrac{11}{5}+\dfrac{1}{12}\\ =-\dfrac{11}{60}+\dfrac{1}{12}\\ =-\dfrac{1}{10}\)
\(d,\dfrac{-1^3}{15}+\left(-\dfrac{2}{3}\right)^2:2\dfrac{2}{3}-\left(-\dfrac{5}{6}\right)\\ =-\dfrac{1}{15}+\dfrac{4}{9}\cdot\dfrac{3}{8}+\dfrac{5}{6}\\ =-\dfrac{1}{15}+\dfrac{1}{6}+\dfrac{5}{6}\\ =\dfrac{1}{10}+\dfrac{5}{6}\\ =\dfrac{14}{15}\)
`e,` Không hiểu đề á c: )
dễ, nhưng phai giai dc câu nay 60% nhan x cong 2 phan 3 = 1 phan 3 nhan 6va 1 phan 3
Giải
Ta có : 5.A = 5 . ( 1 + 5 + 52 + .... + 52019 )
= 5 + 52 +5 3 + ... + 52020
Suy ra : 5A - A = ( 5 + 52 + 53 + ... + 52019 + 52020 ) - ( 1 + 5 + 52 + ... + 52019 )
A = 52020 - 1
Vậy A = 52020 -1
# Chúc bạn học tốt #
5A = 1 + 5.( 5 + 52 + 5x + .... + 52019 )
5A = 1 + 52 + 5x +....+ 52020
5A - A = 1 + ( 52 + 5x +.....+ 52020 ) - ( 5 + 52 + 5x +.....+ 52019 )
4A = 1 + 52020 - 5
A = 1 + ( 52020 - 5 ) : 4
Sai thì thôi bn nhé !!!
Âm hai mũ mười lăm trên hai mũ mười hai = (-2)15/212=(-2)3=-8
(-2)15/212=212.(-2)3/212=(-2)3=8
Chúc bạn học tốt!