Tính tổng A= 1.2 + 3.4 + 5.6 + 7.8 + ... + 98.99
Sử dụng kết quả câu A tính:
C = 1.99 + 2.98 + 3.97 + 4.96+... +98.1
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\(a,A=1\cdot2+2\cdot3+...+98\cdot99\\ 3A=1\cdot2\cdot3+2\cdot3\cdot3+3\cdot4\cdot3+...+98\cdot99\cdot3\\ 3A=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+3\cdot4\left(5-2\right)+...+98\cdot99\left(100-97\right)\\ 3A=1\cdot2\cdot3-1\cdot2\cdot3+2\cdot3\cdot4-2\cdot3\cdot4+3\cdot4\cdot5-...-97\cdot98\cdot99+98\cdot99\cdot100\\ 3A=98\cdot99\cdot100=970200\\ A=323400\)
\(b,B=1^2+2^2+3^3+...+98^2\\ B=1\left(2-1\right)+2\left(3-1\right)+3\left(4-1\right)+...+98\left(99-1\right)\\ B=\left(1\cdot2+2\cdot3+3\cdot4+...+98\cdot99\right)-\left(1+2+...+98\right)\\ B=323400-\left[\left(98+1\right)\left(98-1+1\right):2\right]\\ B=323400-4851=318549\\ c,C=1\cdot99+2\left(99-1\right)+3\left(99-2\right)+...+98\left(99-97\right)+99\left(99-98\right)\\ C=1\cdot99+2\cdot99-1\cdot2+3\cdot99-2\cdot3+...+98\cdot99-97\cdot98+99\cdot99-98\cdot99\\ C=99\left(1+2+...+99\right)-\left(1\cdot2+2\cdot3+...+98\cdot99\right)\\ C=99\left[\left(99+1\right)\left(99-1+1\right):2\right]-323400\\ C=490050-323400=166650\)
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:vv hỏi hoài z?
A = 1.2 + 2.3 + 3.4 +..... + 99.100
=> 3A = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
=> 3A = 1.2.(3-0) + 2.3.(4 - 1) + 3.4.(5 - 2) + … + 99.100. (101 - 98)
=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … +99.100.101-98.99.100
=> 3A = 98.99.100
=> A = 99.100.101/3
=> A = 33.100.101 = 333300
\(C=1.99+2.98+3.97+...+98.2+99.1\)
\(=1.99+2.\left(99-1\right)+3.\left(99-2\right)+...+98.\left(99-97\right)+99.\left(99-98\right)\)
\(=1.99+2.99+3.99+...+98.99+99.99-\left(1.2+2.3+...+97.98+98.99\right)\)
\(A=1.99+2.99+...+99.99\)
\(B=1.2+2.3+...+98.99\)
\(A=1.99+2.99+...+99.99\)
\(=99.\left(1+2+...+99\right)\)
\(=99.\frac{99.\left(99+1\right)}{2}=490050\)
\(B=1.2+2.3+...+98.99\)
\(3B=1.2.3+2.3.\left(4-1\right)+...+98.99.\left(100-97\right)\)
\(=1.2.3+2.3.4-1.2.3+...+98.99.100-97.98.99\)
\(=98.99.100\)
\(B=\frac{98.99.100}{3}=323400\)
\(C=A-B=166650\)