1. Rút gon phân số
a) \(\frac{3737-101}{7474-202}\)
bài b tương tự nên mình tự lm cug đc.
Mong các bn giúp mình với. like cho người nhanh nhứt đó. ^-^
K
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4 tháng 2 2022
a) Các phân số tối giản:
\(\frac{1}{5}\text{ };\text{ }\frac{17}{20}\)
b) Rút gọn:
\(\frac{12}{18}=\frac{12\div6}{18\div6}=\frac{2}{3}\)
\(\frac{15}{95}=\frac{15\div5}{95\div5}=\frac{3}{19}\)
TN
4 tháng 2 2022
a) \(\frac{1}{5}\);\(\frac{17}{20}\)
b) \(\frac{12}{18}\)= \(\frac{2}{3}\);\(\frac{15}{95}\)= \(\frac{3}{19}\)
LM
23 tháng 1 2016
Hello. My name is Duc. Let me introduce myself and my family. I'm 18 this year, a student of a school television. Walking and playing with friends is my hobby. I was born and raised in the province HB. My family has 4 people: parents, my, my sister and me. My father is an engineer. My mother was a doctor. 9 years old and my brother is studying in an elementary school. She studied very hard and is one of the best student in her class. On good days, and with spare time, my family often went on to play with grandparents, it is very meaningful and fun. I feel very happy to be alive in this family.
I love my family very much. I will try to learn and do well to take care of my family. I hope that my family is happy and there is always the best thing.
Thank you for listening to my thoughts.
Wishing you a happy day.
8 tháng 2 2022
143/132=13/12
3535/3737=35/37
~HT~
K cho mình nha mình đang cần tăng SP CẢM ƠN MỌI NHƯỜI
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8 tháng 2 2022
\(\frac{143}{132}=\frac{143:11}{132:11}=\frac{13}{12};\frac{3535}{3737}=\frac{3535:101}{3737:101}=\frac{35}{37}\)
3 tháng 1 2016
a,3535/3737-x=2121/7474
35/37-x=21/74
x=35/37-21/74
x=49/74
b,x/1968-217/984=187/492
x/1968=187/492+217/984
x/1968=197/328
x=197.1967/328
x=????
HX
3 tháng 1 2016
\(\frac{3535}{3737}-x=\frac{2121}{7474}\)
\(x=\frac{3535}{3737}-\frac{2121}{7474}\)
\(x=\frac{7070}{7474}-\frac{2121}{7474}\)
9 tháng 7 2021
Đặt \(A=\frac{1}{5}+\frac{1}{5^3}+...+\frac{1}{5^{101}}\)
\(\Rightarrow25A=5+\frac{1}{5}+\frac{1}{5^3}+...+\frac{1}{5^{99}}\)
\(\Rightarrow25A-A=\left(5+\frac{1}{5}+\frac{1}{5^3}+...+\frac{1}{5^{99}}\right)-\left(\frac{1}{5}+\frac{1}{5^3}+\frac{1}{5^5}+...+\frac{1}{5^{101}}\right)\)
hay \(24A=5-\frac{1}{5^{101}}\)
\(\Rightarrow A=\frac{5-\frac{1}{5^{101}}}{24}\)
\(\Rightarrow A:\left(1-\frac{1}{5^{102}}\right)=\frac{5-\frac{1}{5^{101}}}{24}.\frac{1}{1-\frac{1}{5^{102}}}\)
\(=\frac{5\left(1-\frac{1}{5^{102}}\right)}{24}.\frac{1}{1-\frac{1}{5^{102}}}=\frac{5}{24}\)
3737/7474 = 1/2
101/202 = 1/2
suy ra 1/2 - 1/2 = 0
mình chac chan lun