Tìm x:
x/5=5/6+-19/30
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\(x-\dfrac{4}{12}=-\dfrac{5}{6}\)
⇔\(x-\dfrac{1}{3}=-\dfrac{5}{6}\)
⇔\(x=-\dfrac{1}{2}\)
Bài 1:
\(=\dfrac{-3-39}{42}+\dfrac{-6-11}{17}-\dfrac{1}{6}=-\dfrac{119}{48}\)
Bài 2:
=>x:5=-13/20
hay x=-65/20=-13/4
Bài 1:
\(=\dfrac{-3-39}{32}+\dfrac{-6-11}{17}+\dfrac{-1}{6}=-\dfrac{21}{16}+\dfrac{-1}{6}-1=-\dfrac{119}{48}\)
Bài 2:
\(\Leftrightarrow x:5=-\dfrac{13}{20}\)
hay x=-13/4
\(x\times\dfrac{4}{5}=3-\dfrac{2}{5}\)
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\)
\(x=\dfrac{13}{5}:\dfrac{4}{5}\)
\(x=\dfrac{13}{5}\times\dfrac{5}{4}\)
\(x=\dfrac{13}{4}\)
Chiều dài HCN là :
\(\dfrac{5}{6}:\dfrac{2}{3}=\dfrac{5}{4}\left(m\right)\)
Chu vi HCN là :
\(\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\left(m\right)\)
Đ/s :...
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\\ x=\dfrac{13}{5}\div\dfrac{4}{5}\\ x=\dfrac{13}{4}\)
\(CD=\dfrac{5}{6}\div\dfrac{2}{3}=\dfrac{5}{4}\\ P=\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\)
\(=\left(x^3+x^2\right)-\left(7x^2+7x\right)+\left(19x+19\right)=\left(x+1\right)\left(x^2-7x+19\right)=0\)
Ta thấy: \(x^2-7x+19=x^2-2\times\frac{7}{2}x+\frac{7}{2}^2+\frac{27}{4}=\left(x-\frac{7}{2}\right)^2+\frac{27}{4}\ge\frac{27}{4}\)lớn hơn 0
\(\Rightarrow x+1=0\Rightarrow x=-1\)
\(x^3-6x^2+12x+19=0\)
\(\Leftrightarrow\left(x^3+x^2\right)-\left(7x^2+7x\right)+\left(19x+19\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2-7x+19\right)=0\)
Mà \(x^2-7x+19>0\)với \(\forall x\)
\(\Rightarrow x+1=0\)
\(\Leftrightarrow x=-1\)
Vậy \(x=-1\)
\(\frac{5}{6}+\frac{\left(-19\right)}{30}=\frac{x}{5}\)
\(\frac{25}{30}+\frac{\left(-19\right)}{30}=\frac{x}{5}\)
\(\frac{6}{30}=\frac{x}{5}\)
\(\frac{1}{5}=\frac{x}{5}\)
\(\Rightarrow5x=5\times1\)
\(5x=5\)
\(x=5\div5\)
\(x=1\)
\(\frac{5}{6}+\frac{-19}{30}=\frac{x}{5}\)
\(\Leftrightarrow\frac{x}{5}=\frac{5}{6}+\frac{-19}{30}\)
\(\Leftrightarrow\frac{x}{5}=\frac{25}{30}+\frac{-19}{30}\)
\(\Leftrightarrow\frac{x}{5}=\frac{6}{30}\)
\(\Leftrightarrow\frac{x}{5}=\frac{1}{5}\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
Ta có: x(1+30%)=-1,31
⇒ \(\dfrac{13}{10}\)x =-1,31
⇒ x =-1,31 : \(\dfrac{13}{10}\)
⇒ x = -\(\dfrac{131}{130}\)
x + 30% x = -1,31
\(x+\dfrac{30}{100}x=-1,31\)
x+0,3x=-1,31
x.(0,3+1)=-1,31
x.1,3=-1,31
\(x=\dfrac{-1,31}{1,3}\)
\(x=-\dfrac{131}{130}\)
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
-----------------------
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
\(\dfrac{x}{5}=\dfrac{5}{6}-\dfrac{19}{30}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{6}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow x=1\)
Ta có : \(\dfrac{x}{5}=\dfrac{5}{6}+\left(-\dfrac{19}{30}\right)=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{1}{5}\)
\(\Leftrightarrow5x=5\)
\(\Leftrightarrow x=1\)
Vậy ...