9/24=a/6. Tìm a.
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a, \(x\) - \(\dfrac{2}{7}\) = \(\dfrac{4}{5}\) \(\times\) \(\dfrac{15}{24}\)
\(x\) - \(\dfrac{2}{7}\) = \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{1}{2}\) + \(\dfrac{2}{7}\)
\(x\) = \(\dfrac{11}{14}\)
b, \(x\): \(\dfrac{2}{7}\) = \(\dfrac{9}{8}\) - \(\dfrac{15}{6}\)
\(x\): \(\dfrac{2}{7}\) = - \(\dfrac{11}{8}\)
\(x\) = - \(\dfrac{11}{8}\) \(\times\) \(\dfrac{2}{7}\)
\(x\) = - \(\dfrac{11}{28}\)
\(a.5,6,10,11,15,18,14,16,19\)
\(b.6,9,13,18,24,31,39\)
\(c.1,3,9,27,81\)
\(d.1,3,6,8,16,28,42,62\)
\(A=\left(9\frac{3}{4}:5,2+x.2\frac{7}{24}\right):1\frac{9}{16}=6\)
\(A=\left(9\frac{3}{4}:5,2+x.2\frac{7}{24}\right)=\frac{75}{8}\)
\(A=\left(2\frac{7}{24}.\frac{9}{11}+x.2\frac{7}{24}\right)=\frac{75}{8}\)
\(A=\left[2\frac{7}{24}.\left(\frac{9}{11}+x\right)\right]=\frac{75}{8}\)
\(A=\frac{9}{11}+x=\frac{45}{11}\)
\(x=\frac{45}{11}-\frac{9}{11}\)
\(x=\frac{36}{11}\)
a: \(\left(x+1\right)^3+\left(x-2\right)^3=2x^3+2\left(2x-1\right)^2-9\)
\(\Leftrightarrow x^3+3x^2+3x+1+x^3-6x^2+12x-8=2x^3+2\left(4x^2-4x+1\right)-9\)
\(\Leftrightarrow2x^3-3x^2+15x-7=2x^3+8x^2-8x-7\)
\(\Leftrightarrow-11x^2+23x=0\)
\(\Leftrightarrow x\left(-11x+23\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{23}{11}\end{matrix}\right.\)
a) S
b) S
c) Đ
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