Tìm x
b. 9 × ( x + 5 ) = 729
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b. 9 × ( x + 5 ) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 – 5
x =76
b. 9 × ( x + 5) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 - 5
x = 76
a) (9458-x)x5=41195 b) (9x x)x6=23490
9458-x =41195:5 9 x x =23490:6
9458-x =8239 9 x x =3916
x=9458-8239 x = 3915:9
x=1219 x=435
c)9x(x+5)=729
x+5=729:9
x+5=81
x=81-5
x=76 k mk nha
a) (9458 - X) x 5 = 41195
9458 - X = 41195 : 5
9458 - X = 8239
X = 9458 - 8239
X = 1219
b) (9 x X) x 6 = 23490
9 x X = 23490 : 6
9 x X = 3915
X = 3915 : 9
X = 435
c) 9 x (X + 5) = 729
X + 5 = 729 : 9
X + 5 = 81
X = 81 - 5
X = 76
`Answer:`
\(\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+...+\left(x+\frac{1}{729}\right)=\frac{4209}{729}\)
\(\Leftrightarrow\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{3^2}\right)+\left(x+\frac{1}{3^3}\right)+...+\left(x+\frac{1}{3^6}\right)=\frac{4209}{729}\)
\(\Leftrightarrow6x+\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)=\frac{4209}{729}\text{(*)}\)
Đặt \(N=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\)
\(\Leftrightarrow3N=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^5}\)
\(\Leftrightarrow3N-N=\left(1+\frac{1}{3}+\frac{1}{3^2}+..+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)\)
\(\Leftrightarrow2N=1-\frac{1}{3^6}\)
\(\Leftrightarrow2N=\frac{728}{729}\)
\(\Leftrightarrow N=\frac{364}{729}\)
\(\text{(*)}\Leftrightarrow6x+\frac{364}{729}=\frac{4209}{729}\)
\(\Leftrightarrow6x=\frac{3845}{729}\)
\(\Leftrightarrow x=\frac{3845}{4374}\)
1)
1200 : 24 - ( 17 - x ) = 36
50 - ( 17 - x ) = 36
17 - x = 50 - 36
17 - x = 14
x = 17 - 14
x = 3
9 x ( x + 5 ) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 - 5
x = 76
1200:24-(17-x)=36 9.(x+5)=729
50 -(17-x)=36 x+5 =729:9
17-x =50-36 x+5 =81
17-x =14 x =81-5
x =17-14 x =76
x =3
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\(\frac{x^8}{9}=729\Leftrightarrow x^8=729.9\)
\(\Leftrightarrow x^8=6561\)
\(\Leftrightarrow x^8=\left(\pm3\right)^8\)
\(\Rightarrow x=3;-3\)
Nếu bạn chưa học số âm thì\(x=3\)
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6 : 1 : 2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6:2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 3
\(x\) = 3 : \(\dfrac{1}{4}\)
\(x\) = 12
= 9 * ( x + 5 ) = 729
= ( 729 : 9 ) - 5 = x
= 81 - 5 = x
= 76 = x
Vậy x = 76
Thử : 9 * ( 76 + 5 ) = 729
= 9 * 81 = 729
Đáp số : 76
b. 9 × ( x + 5 ) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 – 5
x =76