Thực hiện phép tính:
(2+1)(22+1)(24+1)...(2256+1)
Help me!
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a)\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)
\(=\frac{5}{9}:\left[-\frac{3}{22}+-\frac{3}{5}\right]\)
\(=\frac{5}{9}:\frac{-81}{110}\)
\(=\frac{-550}{729}\)
Ta có:
\(\left(x-1\right).\left(x+1\right).\left(x+2\right)\)
\(=\left(x^2+x-x-1\right).\left(x+2\right)\)
\(=\left(x^2-1\right).\left(x+2\right)\)
\(=x^3+2x^2-x-2\)
\(60-\left[15.2+\left(4+1^{35}\right)^2\right]\)
\(\Rightarrow60-\left[30+\left(4+1\right)^2\right]\)
\(\Rightarrow60-\left[30+25\right]\)
\(\Rightarrow60-55\)
\(\Rightarrow5\)
a: \(=-\left(10x^2+15x-8x-12\right)=-10x^2-7x+12\)
1 ( 131,4 - 80,8 ) : 2,3 + 21,84 x 2 = 50,6 : 2,3 + 43,68 = 22 + 43,68= 65,68
1/2*3+1/3*4+1/4*5 + 1/5*6 + .... + 1/99 * 100
= 1/2 -1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 +..... + 1/99 - 1/100
= 1/2 - 1/100
= 49/100 nha bạn !
1/2x3+1/3x4+1/4x5+1/5x6+....+1/99x100
=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+....+1/99-1/100
=1/2-1/100=49/100
`(2 1/3 + 3 1/2): (-4 1/6 + 3 1/7) +7,5`
`=(7/3 +7/2) : (-25/6 + 22/7) + 15/2`
`=35/6 : (-43/42) + 15/2`
`=-245/43+15/2`
`=155/86`
\(=1.\left(2+1\right)\left(2^2+1\right)...\left(2^{256}+1\right)=\left(2-1\right)\left(2+1\right)...\left(2^{256}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{256}+1\right)=\left(2^4-1\right)...\left(2^{256}+1\right)=....=2^{512}-1\)
A= (2-1) (2+1) (22+1) ........ + 1
= (22-1)(22+1) ......... (2256+1)
= (24-1) (24+ 1) ......... (2256+1)
................
= [(2256)2 –1] + 1
= 2512