Thực hiện phép tính(hợp lý nếu có thể):
20\(\dfrac{\text{2}}{\text{5}}\) : \(\dfrac{\text{5}}{\text{6}}\) - 35\(\dfrac{\text{2}}{\text{3}}\) : \(\dfrac{\text{5}}{\text{6}}\) -|-\(\dfrac{\text{3}}{\text{4}}\)|
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\(=\dfrac{2}{3}+\dfrac{1}{5}-\dfrac{2}{3}-4\)
\(=\dfrac{1}{5}-4=\dfrac{-19}{5}\)
Giải:
1) (-8/13:3/7+-5/13:3/7).(-4)3.|-3|/7
=[7/3.(-8/13+-5/13)].-192/7
=[7/3.(-1)].-192/7
=-7/3.-192/7
=64
2) 75%-(5/2+5/3)+(-1/2)2
=3/4-25/6+1/4
=(3/4+1/4)-25/6
=1-25/6
=-19/6
Chúc bạn học tốt!
1) \(\left(\dfrac{-8}{13}:\dfrac{3}{7}+\dfrac{-5}{13}:\dfrac{3}{7}\right).\dfrac{\left(-4\right).|-3|}{7}\)
= \(\left[\left(\dfrac{-8}{13}+\dfrac{-5}{13}\right):\dfrac{3}{7}\right].\dfrac{-64.3}{7}\)
= \(\left[-1:\dfrac{3}{7}\right].\dfrac{-192}{7}\)
= \(\dfrac{-7}{3}.\dfrac{-192}{7}\)
= \(64\)
2) \(75\%-\left(\dfrac{5}{2}+\dfrac{5}{3}\right)+\left(-\dfrac{1}{2}\right)^2\)
= \(\dfrac{3}{4}-\dfrac{25}{6}+\dfrac{1}{4}\)
= \(\left(\dfrac{3}{4}+\dfrac{1}{4}\right)-\dfrac{25}{6}\)
= \(1-\dfrac{25}{6}\)
= \(\dfrac{-19}{6}\)
Chúc bạn học tốt !
`a)1/7xx2/7+1/7xx5/7+6/7`
`=1/7xx(2/7+5/7)+6/7`
`=1/7xx1+6/7`
`=1/7+6/7=1`
`b)6/11xx4/9+6/11xx7/9-6/11xx2/9`
`=6/11xx(4/9+7/9-2/9)`
`=6/11xx9/9`
`=6/11`
Sorry nãy ghi thiếu.
`c)4/25xx5/8xx25/4xx24`
`=(4xx5xx25xx24)/(25xx8xx4)`
`=(4xx5xx24)/(4xx8)`
`=(5xx24)/8`
`=5xx3=15`
c: \(E=\dfrac{\left(x-5\right)^2}{x\left(x-5\right)}=\dfrac{x-5}{x}\)
a: \(=2\sqrt{3}-2+10+5\sqrt{3}+3+\sqrt{3}=8\sqrt{3}+11\)
Lời giải:
Gọi tích trên là $A$. Ta có:
$A=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}\times \frac{5}{6}$
$=\frac{1\times 2\times 3\times 4\times 5}{2\times 3\times 4\times 5\times 6}=\frac{1}{6}$
\(=\dfrac{102}{5}\cdot\dfrac{6}{5}-\dfrac{107}{3}\cdot\dfrac{6}{5}-\dfrac{3}{4}\)
\(=\dfrac{6}{5}\cdot\dfrac{-229}{15}-\dfrac{3}{4}\)
\(=\dfrac{-458}{25}-\dfrac{3}{4}=-\dfrac{1907}{100}\)
= 102/5 x 6/5 - 107/3 x 6/5 - 3/4
= 6/5 x ( 102/5 - 107/3 ) - 3/4
= 6/5 x -229/15 - 3/4
= -458/25 - 3/4
= -1907/100