4/3×6+4/6×9+4/9×12+4/12×15
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\(\frac{4^8.3^{12}.27^2}{6^{12}.9^3}\)
= \(\frac{\left(2^2\right)^8.3^{12}.27^2}{\left(2.3\right)^{12}.\left(3^2\right)^3}\)
= \(\frac{2^{16}.3^{12}.27^2}{2^{12}.3^{12}.27^2}\)
= \(\frac{2^{16}}{2^{12}}\)= 24 = 16
\(\frac{4}{3x6}\)+ \(\frac{4}{6x9}\)+ \(\frac{4}{9x12}\)+ \(\frac{4}{12x15}\)
= \(\frac{4}{18}\)+ \(\frac{4}{54}\)+ \(\frac{4}{108}\)+ \(\frac{4}{180}\)
= \(\frac{2}{9}\)+ \(\frac{2}{27}\)+ \(\frac{1}{27}\)+ \(\frac{1}{45}\)
= \(\frac{2}{27}\)+ \(\frac{1}{27}\)+ \(\frac{2}{9}\)+ \(\frac{1}{45}\)
= \(\frac{1}{9}\)+ \(\frac{2}{9}\)+ \(\frac{1}{45}\)
=\(\frac{3}{9}\)+ \(\frac{1}{45}\)
= \(\frac{4}{45}\)
126 x 56 + 94
= (12 x 5)6 + 94
= 606 + 94
= 46656000000 + 6561
=46656006561
a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)