29-(10+29)=x-(27-9) giúp mình nha mình cần gấp
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\(\dfrac{9}{10}\times\left(\dfrac{11}{29}+\dfrac{2}{29}+\dfrac{16}{29}\right)=\dfrac{9}{10}\times\dfrac{29}{29}=\dfrac{9}{10}\times1=\dfrac{9}{10}\)
29 - (10 + 29) = x - (27 - 9)
29 - 39 = x - (27 - 9)
-10 = x - (27 - 9)
-10 = x - 18
⇔ x - 18 = -10
x = (-10) +18
x = 8
Vậy x = 8
29 - (10 + 29) = x - (27 - 9)
29 - 39 = x - 18
-10 = x - 18
⇔ x - 18 = -10
x = (-10) + 18
x = 8
29-(10+29)=x-(27-9)
20-10-9=x-27+9
10-9=x-36
1=x-36
x-36=1
x=1+36
x=37
29 - ( 209/10 * x - 80 ) : 2010/29 = 0
( 209/10 * x - 80 ) : 2010/29 = 29 - 0
( 209/10 * x - 80 ) : 2010/29 = 29
( 20,9 * x -80 ) = 29 * 2010/ 29
( 20,9 * x -80 ) = 2010
20,9 * x = 2010 + 80
20,9 * x = 2090
x = 2090 : 20,9
x = 100
HOK TỐT
29 - (\(\frac{209}{10}\)*X - 80 ) : \(\frac{2010}{29}\)=0
giải
(\(\frac{209}{10}\)* X - 80 ) : \(\frac{2010}{29}\)= 29
\(\frac{209}{10}\)* X - 80 )=29 x \(\frac{2010}{29}\)
\(\frac{209}{10}\)* X - 80 = 2010
\(\frac{209}{10}\)* X = 2010 + 80
\(\frac{209}{10}\)* X= 2090
X= 2090 : \(\frac{209}{10}\)
X= 2090 * \(\frac{10}{209}\)
X=100
Sửa đề: \(\dfrac{1}{1.9}\rightarrow\dfrac{9}{9.19}\)
Giải:
\(N=\dfrac{9}{9.19}+\dfrac{9}{19.29}+\dfrac{9}{29.39}+...+\dfrac{9}{2019.2029}\)
\(N=\dfrac{9}{10}.\left(\dfrac{10}{9.19}+\dfrac{10}{19.29}+\dfrac{10}{29.39}+...+\dfrac{10}{2019.2029}\right)\)
\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{29}+\dfrac{1}{29}-\dfrac{1}{39}+...+\dfrac{1}{2019}-\dfrac{1}{2029}\right)\)
\(N=\dfrac{9}{10}.\left(\dfrac{1}{9}-\dfrac{1}{2029}\right)\)
\(N=\dfrac{9}{10}.\dfrac{2020}{18261}\)
\(N=\dfrac{202}{2029}\)
Ta có:\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
=\(\frac{2^{29}.3^{18}.(5.2-9)}{2^{28}.3^{18}.(5.3-7.2)}\)=\(\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)=\(\frac{2}{1}\)= 2
bai 1
cach 1 9(9-3-5)=9.1=9
cach 2 81-27-45=9
bai 2
cách 1 551-337-551+247=-90
c 2 29.6-19.16=-90
a) cách 1 :
\(81-9\times\left(3+5\right)\)
\(=81-9\times8\)
\(=81-72\)
\(=9\)
cách 2 :
b) \(81-9\times\left(3+5\right)\)
\(=81-\left(9\times3+9\times5\right)\)
\(=81-\left(27+45\right)\)
\(=81-72\)
\(=9\)
29-(10+29)=x-(27-9)
29-10-29 =x-18
10 =x-18
10+18 =x
28 =x