Tìm số tự nhiên a, biết a×b=150 và ƯCLN(a,b)=5
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ƯCLN(a,b)=5
=>\(a=5\cdot x;b=5y\), với điều kiện là ƯCLN(x;y)=1
\(a\cdot b=5\cdot150=750\)
=>\(x\cdot y=30\)
Ta sẽ có bảng sau:
a | 1 | 2 | 3 | 5 |
x | 5 | 10 | 15 | 25 |
b | 30 | 15 | 10 | 6 |
y | 150 | 75 | 50 | 30 |
=>Các cặp số (a;b) cần tìm sẽ là (5;150); (150;5); (10;75); (75;10); (25;30); (30;25)
vì ƯCLN(a,b)=6 (a<b)
a=6m
b=6n
với (m,n)=1,m\(\le\)n
a+b=6m+6n=6(m+n)=84
=>m+n=14
m=1 ,n=13,=>a=6,b=78
m=3,n=11,=>a=18,b=66
m=5,n=9,=>a=30,b=54
m=7,n=7,a=42,b=42
bài còn lại cũng tương tự
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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52542000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 | 542454550212.100000000000000000000000000000000000000000000000000000000000000000000000000000 |
\(ƯCLN\left(a,b\right)=5\Rightarrow\left\{{}\begin{matrix}a=5k\\b=5q\end{matrix}\right.\left(k,q\in N\text{*}\right)\\ ab=250\\ \Rightarrow25kq=250\\ \Rightarrow kq=10=2.5=10.1\)
Mà \(k>q;\left(k,q\right)=1\Rightarrow\left(k;q\right)\in\left\{\left(10;1\right);\left(5;2\right)\right\}\)
\(\Rightarrow\left(a;b\right)\in\left\{\left(50;5\right);\left(25;10\right)\right\}\)