BT1: Tìm n thuộc Z
\(\frac{1}{9}.27^n=3^n\)
\(\left(\frac{3}{7}\right)^n=\frac{81}{2401}\)
BT2: Tính
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(\frac{2.8^4.27^2+4.6^9}{2^7.6^6+2^7.40.9^4}\)
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Q
8 tháng 10 2016
\(A=\frac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^8+2^2\cdot\left(2\cdot3\right)^9}{2^7\cdot6^7+2^7\cdot\left(2^3\cdot5\right).\left(3^2\right)^4}\)
\(A=\frac{2\cdot2^{12}\cdot3^{24}+2^2\cdot\left(2\cdot3\right)^9}{12^7+2^7\cdot\left(2^3\cdot5\right)\cdot3^8}\)
Đến đó thì bí
6 tháng 11 2017
a, \(\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
=\(\dfrac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^2+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot\left(3^2\right)^4}\)
=\(\dfrac{2\cdot2^{12}\cdot3^6+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
=\(\dfrac{2^{11}\cdot3^6\cdot\left(2^2+3^3\right)}{2^{10}\cdot3^7\cdot\left(2^4+5\cdot3\right)}\)
=\(\dfrac{2^{11}\cdot3^6\cdot31}{2^{10}\cdot3^7\cdot31}\)
=\(\dfrac{2}{3}\)
6 tháng 11 2017
b, \(\dfrac{\dfrac{8}{27}\cdot\dfrac{9}{16}\cdot\left(-1\right)}{\dfrac{4}{25}\cdot\dfrac{-125}{1728}}\)
=\(\dfrac{\dfrac{8\cdot9\cdot\left(-1\right)}{27\cdot16}}{\dfrac{4\cdot\left(-125\right)}{25\cdot1728}}\)
=\(\dfrac{\dfrac{-1}{6}}{\dfrac{-5}{432}}\)
=\(\dfrac{-1}{6}\cdot\dfrac{-432}{5}\)
=\(\dfrac{72}{5}\)
2 tháng 7 2019
a)\(\frac{11^4.6-11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5+9^8.7}\)
\(=1.6:\frac{9^8.3-9^8.9}{9^8.\left(5+7\right)}\)
\(=6:\frac{9^8.\left(3-9\right)}{9^8.12}\)
\(=6:\frac{9^8.\left(-6\right)}{9^8.12}\)
\(=6:\left(-\frac{6}{12}\right)\)
\(=6:\left(-\frac{1}{2}\right)\)
\(=-12\)
b) 3/5 : ( -1/5-1/6)+3/5:(-1/3-16/15) ( mình chuyển về ps luôn )
=3/5: (-11/30) + 3/5 : (-7/5)
=3/5:[-11/30+(-7/5)]
=3/5:53/30
=18/53
c) (1/2-13/14):5/7-(-2/21+1/7):5/7
= -3/7:5/7-1/21:5/7
=(-3/7-1/21):5/7
=-10/21:5/7
=-2/3
câu b vá c mình làm tắt nha. chúc bạn học tốt
13 tháng 9 2019
\(D=\frac{2\cdot8^9\cdot27+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
\(=\frac{2^{28}\cdot3^3+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
\(=\frac{3^3\cdot2^{11}\left(2^{17}+3^6\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}\)
\(=\frac{2^{18}+2\cdot3^6}{6^4+3^5}\)
Đúng ko ta.Kết quả hổng đẹp chút nào:(((
13 tháng 9 2019
\(E=\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}\right)^2\cdot\left(-1\right)^5}{\left(\frac{2}{5}\right)^2\cdot\left(\frac{-5}{12}\right)^3}\)
\(E=\frac{\frac{2^3}{3^3}\cdot\frac{3^2}{4^2}\cdot\left(-1\right)}{\frac{2^2}{5^2}\cdot\frac{\left(-5\right)^3}{12^3}}\)
\(E=\frac{\frac{-2}{3\cdot4}}{\frac{2^2}{5^2}\cdot\frac{-5^3}{2^6\cdot3^3}}=-\frac{\frac{1}{3}}{-\frac{5}{2^4\cdot3^3}}=\frac{2^4\cdot3^2}{5}\)
TN
2
MT
27 tháng 6 2015
\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^7.2^7.3^7+2^7.2^3.5.3^8}=\frac{2^{13}.3^6+2^{11}.3^9}{2^{14}.3^7+2^{10}.3^8.5}\)
=\(\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^4\left(2^4+3.5\right)}=\frac{2.3^2.31}{31}=2.3^2=18\)
MT
27 tháng 6 2015
mjk sửa nè
\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^7.2^7.3^7+2^7.2^3.5.3^8}=\frac{2^{13}.3^6+2^{11}.3^9}{2^{14}.3^7+2^{10}.3^8.5}\)
=\(\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^7\left(2^4+3.5\right)}=\frac{2.31}{3.31}=\frac{2}{3}\)
1/9.27nn=3n
1/9=3n:27n
1/9=(1/9)n
=>n=1