Đề: tính giá trị của biểu thức có thể tính nhanh
A.400+{106-[2^3+(4.2^3-6.5)]}
B.800:{111-[3^2+(2^3.5-19.2]}
K
Khách
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14 tháng 10 2021
\(1,\\ a,\Leftrightarrow4^{5-x}=4^2\Leftrightarrow5-x=2\Leftrightarrow x=3\\ b,\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\\ c,\Leftrightarrow2x+1=3\Leftrightarrow x=2\\ 2,\\ a,3^{100}=\left(3^2\right)^{50}=9^{50}\\ b,2^{98}=\left(2^2\right)^{49}=4^{49}< 9^{49}\\ c,5^{30}=5^{29}\cdot5< 6\cdot5^{29}\\ d,3^{30}=\left(3^3\right)^{10}=27^{10}>8^{10}\\ 4,\\ a,\Leftrightarrow5\left(x-10\right)=10\\ \Leftrightarrow x-10=2\Leftrightarrow x=12\\ b,\Leftrightarrow3\left(70-x\right)+5=92\\ \Leftrightarrow3\left(70-x\right)=87\\ \Leftrightarrow70-x=29\\ \Leftrightarrow x=41\\ c,\Leftrightarrow16+x-5=315-230=85\\ \Leftrightarrow x=74\\ d,\Leftrightarrow2^x-5+74=707:\left(16-9\right)=707:7=101\\ \Leftrightarrow2^x=32=2^5\\ \Leftrightarrow x=5\)
KB
1
H9
HT.Phong (9A5)
CTVHS
8 tháng 8 2023
a) \(\dfrac{2^6\cdot5^5}{10^5}\)
\(=\dfrac{2^6\cdot5^5}{2^5\cdot5^5}\)
\(=2\)
b) \(\dfrac{3^6\cdot5^7}{15^6}\)
\(=\dfrac{3^6\cdot5^7}{3^6\cdot5^6}\)
\(=5\)
HN
27 tháng 3 2018
Câu 1:
\(A=\frac{2^5.7+2^5}{2^5.3-2^5}\)= \(\frac{2^5.8}{2^5.2}\)= 4
Vậy A = 4
Câu 2:
\(B=2^3.5^3-3.\left\{400-\left[673-2^3.\left(7^8:7^6+7^0\right)\right]\right\}\)
\(B=8.125-3.\left\{400-\left[673-8.\left(7^2+1\right)\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-8.\left(49+1\right)\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-8.50\right]\right\}\)
\(B=1000-3.\left\{400-\left[673-400\right]\right\}\)
\(B=1000-3.\left\{400-273\right\}\)
\(B=1000-3.127\)
\(B=1000-381\)
\(B=619\)
Vậy B = 619
30 tháng 7 2018
\(A=\frac{25^3.5^5}{6.5^{10}}=\frac{\left(5^2\right)^3.5^5}{6.5^{10}}=\frac{5^6.5^5}{6.5^{10}}=\frac{5^{11}}{6.5^{10}}=\frac{5}{6}\)
30 tháng 7 2018
\(B=\frac{2^5.6^3}{8^2.9^2}=\frac{2^5.2^3.3^3}{\left(2^3\right)^2.\left(3^2\right)^2}=\frac{2^8.3^3}{2^6.3^4}=\frac{4}{3}\)
27 tháng 3 2017
a) = 324 + 6 + 64 x 10
= 324 + 6 + 640
= 330 + 640
= 970 ( vì nhân chia trước cộng trừ sau )
b) = ( 2000 - 333 x 2 ) : ( 333 - 111 x 3 )
= ( 2000 - 333 x 2 ) : ( 333 - 333 )
= 0 ( vì số nào nhân với 0 đều bằng 0 )
c) = ( 666 - 666 ) : ( 150 - 50 x 2 )
= 0 ( vì 0 chia cho số nào cũng bằng 0 )
tk mk nha bạn !
CM
15 tháng 1 2018
a) 927 – 10 x 2 = 927 – 20
= 907
b) 163 + 90 : 3 = 163 + 30
= 193
c) 90 + 10 x 2 = 90 + 20
= 110
d) 106 – 80 : 4 = 106 – 20
= 86
NT
0
11 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=\dfrac{2^3}{1}=2^3=8\)
_____
\(\dfrac{4^8\cdot9^4}{6^6\cdot8^3}\)
`=`\(\dfrac{\left(2^2\right)^8\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^6\cdot3^6\cdot2^9}\)
`=`\(\dfrac{2^{16}\cdot3^8}{2^{15}\cdot3^6}\)
`=`\(\dfrac{3^2}{2}\) `=`\(\dfrac{9}{2}\)
______
\(\dfrac{27^4\cdot2^3-3^{10}\cdot4^3}{6^4\cdot9^3}\)
`=`\(\dfrac{\left(3^3\right)^4\cdot2^3-3^{10}\cdot\left(2^2\right)^3}{2^4\cdot3^4\cdot\left(3^2\right)^3}\)
`=`\(\dfrac{3^{12}\cdot2^3-3^{10}\cdot2^6}{2^4\cdot3^4\cdot3^6}\)
`=`\(\dfrac{3^{10}\cdot\left(3^2\cdot2^3-2^6\right)}{3^{10}\cdot2^4}\)
`=`\(\dfrac{72-2^6}{2^4}=\dfrac{8}{16}=\dfrac{1}{2}\)
11 tháng 7 2023
\(\dfrac{2^8-2^3}{2^5-1}=\dfrac{2^3\left(2^5-1\right)}{2^5-1}=2^3=8\)
\(\dfrac{4^8.9^4}{6^6.8^3}=\dfrac{2^{16}.3^8}{2^6.3^6.2^9}=2.3^2=18\)
\(\dfrac{27^4.2^3-3^{10}.4^3}{6^4.9^3}=\dfrac{3^{12}.2^3-3^{10}.2^6}{2^4.3^4.3^6}=\dfrac{2^3.3^{10}.\left(3^2-2^3\right)}{2^4.3^{10}}=\dfrac{9-8}{2}=\dfrac{1}{2}\)
A) 400 + { 106 - [ 23 + ( 4.23 - 6.5 )]}
= 400 + { 106 - [ 8 + ( 4.8 - 30 )]}
= 400 + { 106 - [ 8 + ( 32 - 30 )]}
= 400 + { 106 - [ 8 + 2 ]}
= 400 + { 106 - 10 }
= 400 + 96
= 496
B) 800 : { 111 - [ 32 + ( 23 .5 - 19.2 )]}
= 800 : { 111 - [ 9 + ( 8.5 - 38 )]}
= 800 : { 111 - [ 9 + ( 40 - 38 )]}
= 800 : { 111 - [ 9 + 2 ]
= 800 : { 111 - 11 }
= 800 : 100
= 8
\(A,400+\left\{106-\left\{2^3+\left(4.2^3-6.5\right)\right\}\right\}\)
\(A,=400+\left\{106-\left\{8+\left(4.8-6.5\right)\right\}\right\}\)
\(A,=400+\left\{106-\left\{8+\left(32-30\right)\right\}\right\}\)
\(A,=400+\left\{106-\left(8+2\right)\right\}\)
\(A,=400+\left(106-10\right)\)
\(A,=400+96\)
\(A,=496\)
\(B,800:\left\{111-\left\{3^2+\left(2^3.5-19.2.\right)\right\}\right\}\)
\(B,=800:\left\{111-\left\{9+\left(8.5-19.2\right)\right\}\right\}\)
\(B,=800:\left\{111-\left\{9+\left(40-38\right)\right\}\right\}\)
\(B,=800:\left\{111-\left(9+2\right)\right\}\)
\(B,=800:\left(111-11\right)\)
\(B,=800:100\)
\(B,=8\)