giup mik voi. ai giup mik mik se tik diem cho
N=(2/3)^5.(-27/8)^2.729 tất cả trên (3/2)^4 .216
p= 2.8^4.27^2+4.6^9 tất cả trên 2^7.6^7 + 2^7.40.9^4
Q= (2/3)^3.(-3/4)^2.(-1)^5 / (2/5)^2 . (-5/12)^3
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6 tháng 11 2017
a, \(\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
=\(\dfrac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^2+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot\left(3^2\right)^4}\)
=\(\dfrac{2\cdot2^{12}\cdot3^6+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
=\(\dfrac{2^{11}\cdot3^6\cdot\left(2^2+3^3\right)}{2^{10}\cdot3^7\cdot\left(2^4+5\cdot3\right)}\)
=\(\dfrac{2^{11}\cdot3^6\cdot31}{2^{10}\cdot3^7\cdot31}\)
=\(\dfrac{2}{3}\)
6 tháng 11 2017
b, \(\dfrac{\dfrac{8}{27}\cdot\dfrac{9}{16}\cdot\left(-1\right)}{\dfrac{4}{25}\cdot\dfrac{-125}{1728}}\)
=\(\dfrac{\dfrac{8\cdot9\cdot\left(-1\right)}{27\cdot16}}{\dfrac{4\cdot\left(-125\right)}{25\cdot1728}}\)
=\(\dfrac{\dfrac{-1}{6}}{\dfrac{-5}{432}}\)
=\(\dfrac{-1}{6}\cdot\dfrac{-432}{5}\)
=\(\dfrac{72}{5}\)
AS
1
13 tháng 9 2019
\(D=\frac{2\cdot8^9\cdot27+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
\(=\frac{2^{28}\cdot3^3+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
\(=\frac{3^3\cdot2^{11}\left(2^{17}+3^6\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}\)
\(=\frac{2^{18}+2\cdot3^6}{6^4+3^5}\)
Đúng ko ta.Kết quả hổng đẹp chút nào:(((
13 tháng 9 2019
\(E=\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}\right)^2\cdot\left(-1\right)^5}{\left(\frac{2}{5}\right)^2\cdot\left(\frac{-5}{12}\right)^3}\)
\(E=\frac{\frac{2^3}{3^3}\cdot\frac{3^2}{4^2}\cdot\left(-1\right)}{\frac{2^2}{5^2}\cdot\frac{\left(-5\right)^3}{12^3}}\)
\(E=\frac{\frac{-2}{3\cdot4}}{\frac{2^2}{5^2}\cdot\frac{-5^3}{2^6\cdot3^3}}=-\frac{\frac{1}{3}}{-\frac{5}{2^4\cdot3^3}}=\frac{2^4\cdot3^2}{5}\)
8 tháng 10 2023
a: \(A=\dfrac{3^3\cdot2^3+3^3\cdot2^2+3^3\cdot1}{-13}=\dfrac{27\left(2^3+2^2+1\right)}{-13}=-27\)
b: \(B=\dfrac{2\cdot2^{12}\cdot3^6+2^{11}\cdot3^9}{2^3\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot3^8}\)
\(=\dfrac{2^{13}\cdot3^6+2^{11}\cdot3^9}{2^{10}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
\(=\dfrac{2^{11}\cdot3^6\left(2^2+3^3\right)}{2^{10}\cdot3^7\left(1+5\cdot3\right)}=\dfrac{2}{3}\cdot\dfrac{4+27}{1+15}=\dfrac{2}{3}\cdot\dfrac{31}{16}=\dfrac{31}{24}\)
c: \(C=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{35}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)
\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{29}\cdot3^{18}\left(5\cdot2^6-7\right)}=\dfrac{10-9}{5\cdot64-7}=\dfrac{1}{313}\)